如何在Pygame中从用户获取文本输入?

时间:2013-01-01 14:44:34

标签: python pygame

如何从用户进行pygame打印输入:

我正在尝试让用户键入内容并将pygame打印在屏幕上。

这是我目前的计划:

import pygame, pygame.font, pygame.event, pygame.draw, string
from pygame.locals import *

def get_key():
  while 1:
    event = pygame.event.poll()
    if event.type == KEYDOWN:
      return event.key
    else:
      pass

def display_box(screen, message):
  "Print a message in a box in the middle of the screen"
  fontobject = pygame.font.Font(None,18)
  pygame.draw.rect(screen, (0,0,0),
                   ((screen.get_width() / 2) - 100,
                    (screen.get_height() / 2) - 10,
                    200,20), 0)
  pygame.draw.rect(screen, (255,255,255),
                   ((screen.get_width() / 2) - 102,
                    (screen.get_height() / 2) - 12,
                    204,24), 1)
  if len(message) != 0:
    screen.blit(fontobject.render(message, 1, (255,255,255)),
                ((screen.get_width() / 2) - 100, (screen.get_height() / 2) - 10))
  pygame.display.flip()

def ask(screen, question):
  "ask(screen, question) -> answer"
  pygame.font.init()
  current_string = []
  display_box(screen, question + ": " + string.join(current_string,""))
  while 1:
    inkey = get_key()
    if inkey == K_BACKSPACE:
      current_string = current_string[0:-1]
    elif inkey == K_RETURN:
      break
    elif inkey == K_MINUS:
      current_string.append("_")
    elif inkey <= 127:
      current_string.append(chr(inkey))
    display_box(screen, question + ": " + string.join(current_string,""))
  return string.join(current_string,"")

def main():
    screen = pygame.display.set_mode((320,240))
    print ask(screen, "Name") + " was entered"

if __name__ == '__main__': main()

我想要它,所以当用户点击进入时,它会占用屏幕。

帮助我!

1 个答案:

答案 0 :(得分:7)

这是一个blit输入到屏幕的示例脚本。它显示了如何在循环遍历pygame事件队列时修改name字符串。每个帧,屏幕都被清除,名称表面被重建和blit。

import pygame
from pygame.locals import *

def name():
    pygame.init()
    screen = pygame.display.set_mode((480, 360))
    name = ""
    font = pygame.font.Font(None, 50)
    while True:
        for evt in pygame.event.get():
            if evt.type == KEYDOWN:
                if evt.unicode.isalpha():
                    name += evt.unicode
                elif evt.key == K_BACKSPACE:
                    name = name[:-1]
                elif evt.key == K_RETURN:
                    name = ""
            elif evt.type == QUIT:
                return
        screen.fill((0, 0, 0))
        block = font.render(name, True, (255, 255, 255))
        rect = block.get_rect()
        rect.center = screen.get_rect().center
        screen.blit(block, rect)
        pygame.display.flip()

if __name__ == "__main__":
    name()
    pygame.quit()

这是gist version

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