Question

我有一个运行愉快的应用程序，但自从我更新到OS3.1并更新了SDK后，应用程序无法登录到远程服务器，将连接字符串传递给stringWithContentsOfUrl函数。

在更新之前，这工作正常，如果我复制NSLog语句中显示的文本字符串并将其粘贴到浏览器中，那么我得到正确的响应，但是，这是回复“LOGIN_ERROR”表示失败

知道为什么现在失败以及如何解决它？

NSString* userName = [[NSUserDefaults standardUserDefaults] stringForKey:@"username_pref"];
    NSString* password = [[NSUserDefaults standardUserDefaults] stringForKey:@"password_pref"];
    NSString* loginUrl = [NSString stringWithFormat:@"https://website.com/API/login?email=%@&password=%@", userName, password];

    NSLog (@"Logging in as %@ using %@ at [%@]", userName, password, loginUrl);

    NSURL* url = [NSURL URLWithString:loginUrl];
    NSString* loginDetails = [NSString stringWithContentsOfURL:url encoding:NSASCIIStringEncoding error:nil];

    if ([loginDetails compare:@"\"LOGIN_ERROR\""] == NSOrderedSame) 
    {
        DLog (@"Login Failed : LOGIN_ERROR");
        self.isLoggedIn = NO;
    }
    else
    {
        DLog (@"Login Success");
        if (userDetails) {
            [userDetails release];
        }

        NSDictionary* jsonData          = [loginDetails JSONValue];

        userDetails                     = [[[DMUserDetails alloc] init] retain];
        userDetails.id                  = [[jsonData objectForKey:@"id"] intValue];
        userDetails.api_token           = [jsonData objectForKey:@"api_token"];
        userDetails.full_name           = [jsonData objectForKey:@"full_name"];
        userDetails.mobile_number       = [jsonData objectForKey:@"mobile_number"];
        userDetails.mobile_host         = [jsonData objectForKey:@"mobile_host"];
        userDetails.email               = [jsonData objectForKey:@"email"];
        userDetails.twitter             = [jsonData objectForKey:@"twitter"];
        userDetails.jabber              = [jsonData objectForKey:@"jabber"];
        userDetails.msn                 = [jsonData objectForKey:@"msn"];
        userDetails.start_page          = [jsonData objectForKey:@"start_page"];
        userDetails.date_format         = [[jsonData objectForKey:@"date_format"] intValue];
        userDetails.time_format         = [[jsonData objectForKey:@"time_format"] intValue];
        userDetails.sort_order          = [[jsonData objectForKey:@"sort_order"] intValue];
        userDetails.timezone            = [jsonData objectForKey:@"timezone"];
        userDetails.tz_offset           = [jsonData objectForKey:@"tz_offset"];
        userDetails.premium_until       = [jsonData objectForKey:@"premium_until"];
        userDetails.default_reminder    = [jsonData objectForKey:@"default_reminder"];

        self.isLoggedIn = YES;
    }

    [self performSelectorOnMainThread:@selector(didFinishLogon) withObject:nil waitUntilDone:NO];

Answer 1

如果您的用户名是电子邮件地址并且其中包含at符号（@），您是否尝试使用％40而不是@来转义URL中的at符号？

Answer 2

最可能的问题是loginDetails为nil，表示检索URL时出错，而不是实际收到“LOGIN ERROR”响应。

传入错误对象并记录错误。

Answer 3

尝试：

NSError *error = nil;
NSString *loginDetails = [NSString stringWithContentsOfURL:url encoding:NSASCIIStringEncoding error:&error];

if (error != nil) {
    NSLog(@"%@", error);
}

更新到OS3.1后stringWithContentsOfUrl失败

3 个答案: