Question

我无法解组嵌套的复杂对象。在下面的xml例子中，“Racing”有一个RacingTicket对象。这可以通过rdf：about链接来实现，这是一个获得RacingTicket的宁静服务调用。

<?xml version='1.0' encoding='UTF-8'?>
<entry xmlns="http://www.w3.org/2005/Atom" xmlns:hl="http://racing.com/horses/holding-location">
    <title type="text">Create Racing Event</title>
    <id>http://www.racing.com/</id>
    <content type="application/xml">
    <racing xmlns="http://racing.com/schema/horses">
        <racingTicket rdf:about="https://racing.com/fast/racingTicket/asdf-asfd-asdf-asdf-asdf" />
        <tracks>
        <track>
            <title>ABX</title>
            <amount>560</amount>
        </track>
        </tracks>
        <racingId>001</racingId>
    </racing>
    </content>
</entry>



Java class

@XmlRootElement
public class Racing implements Serializable {

    @AtomId( prefixUrl = "http://racing.com/fast/racingTicket/" )
    private String id;

    private RacingTicket racingTicket;

    private Tracks tracks;

    private BigDecimal racingId;



    public RacingTicket getRacingTicket() {

    return racingTicket;
    }

    @XmlElement
    public void setRacingTicket( RacingTicket racingTicket ) {

    this.racingTicket = racingTicket;
    }

jaxb unmarshaler返回的对象包含racingTicket类的所有值为null。请指教，任何帮助表示赞赏。

Answer 1

您可以使用JAXB XmlAdapter在链接和RacingTicket的实例之间进行转换。

示例

Adding links to REST Responses

使用rdf：about解组嵌套的复杂对象

1 个答案: