Question

如何按日期时间列分组自定义小时，例如每5小时或每12小时或每24小时。

Select CreateOn, Count(*) From Table1
Group By ?????

Answer 1

您应该在此示例中选择开始日期/时间“2011-01-01”，然后使用DATEDIFF() function获取开始日期与CreateOn之间的小时差异。然后使用/运算符获取整数区间数（在此示例中为5小时）。

Select 
min(DATEADD(HOUR,DATEDIFF (HOUR,'2011-01-01',CreateOn )/5*5,'2011-01-01')) 
   as Start_time,
max(DATEADD(HOUR,(DATEDIFF (HOUR,'2011-01-01',CreateOn )/5+1)*5,'2011-01-01')) 
   as End_Time,
DATEDIFF (HOUR,'2011-01-01',CreateOn )/5 as Interval_Number, 
Count(*) as _Count
From Table1
Group By DATEDIFF (HOUR,'2011-01-01',CreateOn )/5

Answer 2

如果我理解你的问题，你可以尝试这样的事情：

SELECT CreateOn, Count(*) FROM Table1 GROUP BY (DATEPART(MINUTE, [Date]) % 12)

如何按日期时间列对自定义小时进行分组

2 个答案: