Question

我有一个查询，它在我的贷款表中找到了十大最借出的书籍，但我想将这十个值存储到一个数组中，以便我可以再次使用该数组。这是我到目前为止的代码...感谢您提前提供任何帮助！

//select a database to work with
$selected = mysql_select_db("ds2",$dbhandle)
or die("Could not select examples");

//execute the SQL query and return records
 $result = mysql_query("SELECT book.title, book.book_id, count(book.book_id) AS     count_book_id, loan.book_id  FROM book
      INNER JOIN loan ON book.book_id = loan.book_id
      GROUP BY book.book_id ASC
      ORDER BY count(book.book_id) DESC");

 $titles = array();

while($row = mysql_fetch_array($result))
{
echo $row['title'];
echo "<br>";
}

echo "<br><br>";

for($index = 1; $index <= 10; $index++)
{
array_push($titles,$result[$row]);
print_r($titles);
echo "<br>";

}

Answer 1

而不是echo $row['title']您可以使用下面的代码将它们存储到数组中

$titles[] = $row['title'];

使用数组概念稍后访问它们。

$titles[0]; // 1st item
$titles[1]; //2nd item

您甚至可以使用foreach循环遍历所有项目。

foreach($titles[] as $title)
     echo $title;

下面将允许您获取逗号分隔的字符串（仅在您需要时提供信息）

$comma_separated_titles = implode(",", $titles);

Answer 2

尝试，

while($row = mysql_fetch_array($result))
  {
      echo $row['title']; 
      $arr[] = $row['title'];  //Store in an array          
      echo "<br>";
  }

  echo "<br><br>";

  //Since you need only 10 values, else this for loop is not required.
  for($index = 1; $index <= 10; $index++) 
      $titles[] = $arr[$index]['title'];  

  unset($arr); //unset the original array if you don't need it anymore.
  print_r($titles); //Print top 10 values
  echo "<br>";

Answer 3

你应该在循环中填充数组，而不是在单独的循环中填充：

$count = 0;
while($row = mysql_fetch_array($result))
{
  echo $row['title'];
  echo "<br>";
  if ($count < 10)
  {
    array_push($titles, $row);
  }
  $count++;
}

将字符串保存到数组中

3 个答案: