如何构建包含文件夹结构的数组？

Question

我想构建一个Json输出来列出ExtJS树面板中的文件夹结构。结构应该等同于Json中的这个数组：

Array
(
    [text] => .
    [children] => Array
        (
            [0] => Array
                (
                    [text] => files
                    [children] => 
                )

            [1] => Array
                (
                    [text] => folder 1
                    [children] => 
                )

            [2] => Array
                (
                    [text] => New directory
                    [children] => array(
                        [0] => Array
                            (
                                [text] => sub_1
                                [children] => array(
                                    [0] => Array
                                        (
                                            [text] => sub_1_1
                                            [children] => 
                                        )
                                    [1] => Array
                                        (
                                            [text] => sub_1_2
                                            [children] => 
                                        )                                    
                                )
                            )
                        [1] => Array
                            (
                                [text] => sub_2
                                [children] => 
                            )                             
                    )
                )    
        )    
)

我做了这个功能，通过PHP手册和例子

显示结构

listFolders('../file_uploads/');
function listFolders($dir){
    $dh = scandir($dir);
    echo '<ul>';
    foreach($dh as $folder){
        if($folder != '.' && $folder != '..')
        {
            if(is_dir($dir.'/'.$folder)){
                echo '<li>'.$folder.'</li>';
                listFolders($dir.'/'.$folder);
            }
        }
    }
    echo '</ul>';
}

这输出结构

• 新目录
• sub_1
• sub_1_1
• sub_1_1_1
• sub_1_2
• sub_2
• 文件
• 文件夹1

我想知道如何将此输出转换为上面的数组（或Json）？

溶液

print "<pre>";
print_r(listFolders('../file_uploads/'));

function listFolders($dir)
{
    $dh = scandir($dir);
    $return = array();

    foreach ($dh as $folder) {
        if ($folder != '.' && $folder != '..') {
            if (is_dir($dir . '/' . $folder)) {
                $return[] = array(
                    'text' => $folder,
                    'children' => listFolders($dir . '/' . $folder)
                );
            }
        }
    }
    return $return;
}

Answer 1

请尝试以下代码：

function listFolders($dir)
{
    $dh = scandir($dir);
    $return = array();

    foreach ($dh as $folder) {
        if ($folder != '.' && $folder != '..') {
            if (is_dir($dir . '/' . $folder)) {
                $return[] = array($folder => listFolders($dir . '/' . $folder));
            } else {
                $return[] = $folder;
            }
        }
    }
    return $return;
}

似乎对我有用，但未经过适当的测试。

Answer 2

首先创建一个数组。对于每个创建的目录，使用array_push到数组？

另请查看http://php.net/manual/en/function.scandir.php上的评论。

Answer 3

<?php
error_reporting(0);

$array_folders  = listFolders('../file_uploads/');
echo "<pre>";
print_r($array_folders);

function listFolders($dir){
    global $ret_array;
    $dh = scandir($dir);
    foreach($dh as $folder){
        if($folder != '.' && $folder != '..')
        {
            if(is_dir($dir.'/'.$folder)){
                $ret_array[$dir][]  = $folder;
                listFolders($dir.'/'.$folder);
            }
        }
    }
    return $ret_array;
}
?>

Answer 4

我认为您正在寻找递归目录列表。使用下面的代码我希望它可以帮助你。它对我有用。

<?php
/**
 * Function for recursive directory file list search as an array.
 *
 * @param mixed $dir Main Directory Path.
 *
 * @return array
 */
function listFolderFiles($dir)
{
    $fileInfo     = scandir($dir);
    $allFileLists = [];

    foreach ($fileInfo as $folder) {
        if ($folder !== '.' && $folder !== '..') {
            if (is_dir($dir . DIRECTORY_SEPARATOR . $folder) === true) {
                $allFileLists[$folder . '/'] = listFolderFiles($dir . DIRECTORY_SEPARATOR . $folder);
            } else {
                $allFileLists[$folder] = $folder;
            }
        }
    }

    return $allFileLists;
}//end listFolderFiles()


$dir = listFolderFiles('your searching directory path ex:-F:\xampp\htdocs\abc');
echo '<pre>';
print_r($dir);
echo '</pre>'

?>

Answer 5

要获得完全相同的结果，请遵循以下代码

function listFolderFiles($dir){
    $ffs = scandir($dir);

    unset($ffs[array_search('.', $ffs, true)]);
    unset($ffs[array_search('..', $ffs, true)]);

    // prevent empty ordered elements
    //if (count($ffs) < 1)
    //    return;


    $dirStrArr = array();
    foreach($ffs as $ff){
        if(is_dir($dir.'/'.$ff)) {
            $dirStrArr[]=array('parent' => $ff, 'children' => listFolderFiles($dir . '/' . $ff));
        }else{
            $dirStrArr[]=$ff;
        }
    }
    return $dirStrArr;
}

或者要将文件夹名称作为索引以及索引数组中的子详细信息，您可以按照下面的代码

function listFolderFiles($dir){
    $ffs = scandir($dir);

    unset($ffs[array_search('.', $ffs, true)]);
    unset($ffs[array_search('..', $ffs, true)]);

    // prevent empty ordered elements
    //if (count($ffs) < 1)
    //    return;


    $dirStrArr = array();
    foreach($ffs as $ff){
        if(is_dir($dir.'/'.$ff)) {
            $dirStrArr[$ff]=listFolderFiles($dir . '/' . $ff);
        }else{
            $dirStrArr[]=$ff;
        }
    }
    return $dirStrArr;
}