Question

我正在创建一个包含复制框的可复制div，在原始输入集上，复选框就像单选按钮一样，但是当复制时它仍然只是在第一个而不是第二个工作。

同样在提交时，它只在控制台中返回原始表单的一个值，但没有任何重复值。

非常感谢任何帮助。

JS小提琴：http://jsfiddle.net/dawidvdh/EEd7c/

jQuery的：

//Clone Tracking
var g_counter = 1;
var d_counter = 1;
var dependant = ["dependant"];
var group;
//Clone Tracking
//General Variables
var relation_input_groups = ["relation-group-1"];
//General Variables
//Generate variables
var relation_fields=[0];
var relation_input ="<label>Spouse</label>"+

    "<input type='checkbox' value='spouse' class='relationship' name='relationship' />" +
    "<label>own child</label>"+ 

    "<input type='checkbox' value='ownchild' class='relationship' name='relationship' />" +
    "<label>adopted</label>"+ 

    "<input type='checkbox' value='adopted' class='relationship' name='relationship' />" +
    "<label>stepchild</label>"+ 

    "<input type='checkbox' value='stepchild' class='relationship' name='relationship' />" +
    "<label>parent</label>"+ 

    "<input type='checkbox' value='parent' class='relationship' name='relationship' />" +
    "<label>inlaw</label>"+ 

    "<input type='checkbox' value='inlaw' class='relationship' name='relationship' />" +
    "<label>brother</label>"+ 

    "<input type='checkbox' value='brother' class='relationship' name='relationship' />" +
    "<label>other</label>"+ 

    "<input type='checkbox' value='other' class='relationship' name='relationship' />";
//Generate variables
jQuery(document).ready(function(e) 
{
    //populate jquery generated fields
    jQuery(relation_fields).each(function() 
    {
        jQuery(relation_input).appendTo('#relation-group-1');
    });
    //populate jquery generated fields
    //Cloning Function
    jQuery('#clone').click(function() 
    {
        clone_dependant();
    });
    function clone_dependant() 
    {
        // Store the value of the previous Id to insert the cloned div..
        var oldId = g_counter;
        g_counter++;
        currentdep ='dependant-'+g_counter;
        // Clone the Dependant Div and set a new id
        var $clonedDiv = jQuery('#dependant-1').clone(false).attr('id', 'dependant-'+g_counter);
        var relation_newDiv = 'relation-group-'+ g_counter;
        // Find div's inside the cloned object and set a new id's
        $clonedDiv.find('#relation-group-1').attr('id',"relation-group-" + g_counter );
        // You don't need to Loop thru the inputs to set the value
        $clonedDiv.find('input').val('');
        $clonedDiv.find('input:checkbox').removeAttr('checked');
        // Insert the cloned object 
        $clonedDiv.insertAfter("#dependant-" + oldId);

        relation_input_groups.push(relation_newDiv);
    }
    //Cloning Function
    //Validation
    //submit function
    var $unique = $('input[type="checkbox"]');
    $unique.click(function() 
    {
        $unique.removeAttr('checked');
        $(this).attr('checked', true);
    });

    var result = {};
    var dependants;
    var dep_counter = 0;
    jQuery('#submit').click(function()
    {
        jQuery('.dependant').each(function(k, v)
        {
            dep_counter++
            dependants = {};
            result['dependant'+dep_counter] = [dependants];
            dependants['relationship'] = $(v).find('.relationship:checked').val();
        });
        var jsonData = JSON.stringify(result);
        console.log(jsonData);
    });
});

和HTML：

<div id="dependant-1" class="dependant">
    <div id="label">relationship:</div> <div id="relation-group-1"></div>
</div>

<button id="clone">clone</button>
<button id="submit">submit</button>

提前致谢：）

Answer 1

请参阅：http://jsfiddle.net/EEd7c/1/

var $unique = $('input[type="checkbox"]');
$unique.live("click", function() {
$(this).siblings().removeAttr('checked');
$(this).attr('checked', true);
});

然而Live已被弃用......

或者

$(document).on("click", 'input[type="checkbox"]', function() {
$(this).siblings().removeAttr('checked');
$(this).attr('checked', true);
});

Answer 2

它不起作用的原因是您没有将点击事件附加到新的克隆元素。

$(document).on("click", 'input[type="checkbox"]', function() {
    jQuery(this).siblings(":checked").removeAttr('checked');
});

Answer 3

var $unique = $('input[type="checkbox"]');
$unique.live('click',function() {
    $(this).closest('div').find('input[type="checkbox"]').removeAttr('checked');
    $(this).attr('checked', true);
});

使用live将事件处理程序注册到动态创建的元素。 $ unique变量将仅包含初始的复选框集。

使复选框的行为类似于可复制输入字段中的单选按钮

3 个答案: