我正在尝试计算具有相同背景颜色的单元格数量,并将结果放在google apps脚本中的脚本的其他单元格中,但我不能这样做。我有下一个脚本但没有工作,我不知道哪个是问题:
function countbackgrounds() {
var book = SpreadsheetApp.getActiveSpreadsheet();
var range_input = book.getRange("B3:B4");
var range_output = book.getRange("B6");
var cell_colors = range_input.getBackgroundColors()[0];
var color = "#58FA58";
var count = 0;
for( var i in cell_colors )
if( cell_colors[i] == color ){
range_output.setValue(++count);
}
else {
return count;
}
}
答案 0 :(得分:22)
如果您不想使用Google Sheets Power Tools手动编码,请轻松解决:
答案 1 :(得分:8)
function countbackgrounds() {
var book = SpreadsheetApp.getActiveSpreadsheet();
var sheet = book.getActiveSheet();
var range_input = sheet.getRange("B3:B4");
var range_output = sheet.getRange("B6");
var cell_colors = range_input.getBackgroundColors();
var color = "#58FA58";
var count = 0;
for(var r = 0; r < cell_colors.length; r++) {
for(var c = 0; c < cell_colors[0].length; c++) {
if(cell_colors[r][c] == color) {
count = count + 1;
}
}
}
range_output.setValue(count);
}
答案 2 :(得分:3)
您可以使用以下工作脚本:
/**
* @param {range} countRange Range to be evaluated
* @param {range} colorRef Cell with background color to be searched for in countRange
* @return {number}
* @customfunction
*/
function countColoredCells(countRange,colorRef) {
var activeRange = SpreadsheetApp.getActiveRange();
var activeSheet = activeRange.getSheet();
var formula = activeRange.getFormula();
var rangeA1Notation = formula.match(/\((.*)\,/).pop();
var range = activeSheet.getRange(rangeA1Notation);
var bg = range.getBackgrounds();
var values = range.getValues();
var colorCellA1Notation = formula.match(/\,(.*)\)/).pop();
var colorCell = activeSheet.getRange(colorCellA1Notation);
var color = colorCell.getBackground();
var count = 0;
for(var i=0;i<bg.length;i++)
for(var j=0;j<bg[0].length;j++)
if( bg[i][j] == color )
count=count+1;
return count;
};
然后在您的Google表格中调用此功能:
=countColoredCells(D5:D123,Z11)
答案 3 :(得分:1)
这是一个工作版本:
function countbackgrounds() {
var book = SpreadsheetApp.getActiveSpreadsheet();
var range_input = book.getRange("B3:B4");
var range_output = book.getRange("B6");
var cell_colors = range_input.getBackgroundColors();
var color = "#58FA58";
var count = 0;
for( var i in cell_colors ){
Logger.log(cell_colors[i][0])
if( cell_colors[i][0] == color ){ ++count }
}
range_output.setValue(count);
}
答案 4 :(得分:0)
以前的函数对我不起作用,因此我制作了另一个函数,该函数使用与上述答案之一相同的逻辑:解析单元格中的公式以查找要检查和查找的单元格的引用范围对于有色细胞。 您可以在这里找到详细的描述:Google Script count coloured with reference,但是代码如下:
function countColoured(reference) {
var sheet = SpreadsheetApp.getActiveSheet();
var formula = SpreadsheetApp.getActiveRange().getFormula();
var args = formula.match(/=\w+\((.*)\)/i)[1].split('!');
try {
if (args.length == 1) {
var range = sheet.getRange(args[0]);
}
else {
sheet = ss.getSheetByName(args[0].replace(/'/g, ''));
range = sheet.getRange(args[1]);
}
}
catch(e) {
throw new Error(args.join('!') + ' is not a valid range');
}
var c = 0;
var numRows = range.getNumRows();
var numCols = range.getNumColumns();
for (var i = 1; i <= numRows; i++) {
for (var j = 1; j <= numCols; j++) {
c = c + ( range.getCell(i,j).getBackground() == "#ffffff" ? 0 : 1 );
}
}
return c > 0 ? c : "" ;
}