Question

Google地图标记可以将复杂的svg路径作为其图标，如：

var baseSvg = {
    x1 : "m 0,0 l45,0 l 190,225 l -45,0 l -190,-225 z",
    x2 : "m 225,0 l -45,0 l -190,225 l 45,0 l 190,-225 z"                
};

var baseIcon = {
    path: "M0,0 " + baseSvg["x1"] + baseSvg["x2"],
    fillColor: "#000000",
    fillOpacity: 1,
    scale: .2,
    strokeColor: "black",
    strokeWeight: 0,
    rotation: 15
};

然后送入标记：

var marker = new google.maps.Marker({
    position: new google.maps.LatLng(somelat, somelng),
    icon: baseIcon 
});

一切都好。但它只绘制一种颜色（本例中为黑色）。 那么，它们只能使用单一颜色还是有多种颜色的符号？使用示例代码，x1为红色，x2为绿色。

请注意，这个构造是从这里借来的：How do I indicate transparency in an SVG path in Google Maps API v3?并且它运行良好。

Answer 1

我刚刚做了同样的事情，我认为你必须绘制两个基本相同数据的标记，但是path并且在这种情况下fillColor属性已更改：

var baseSvg = {
        x1 : "m 0,0 l45,0 l 190,225 l -45,0 l -190,-225 z",
        x2 : "m 225,0 l -45,0 l -190,225 l 45,0 l 190,-225 z"                
    },
    baseIcon = {
        fillOpacity: 1,
        scale: .2,
        strokeColor: "black",
        strokeWeight: 0,
        rotation: 15
    },
    markerPos = new google.maps.LatLng(somelat, somelng),
    // psuedo code for cloning an object since that 
    // is out of scope for this question
    greenIcon = Object.clone(baseIcon),
    redIcon = Object.clone(baseIcon);

greenIcon.path = baseSvg.x1;
greenIcon.fillColor = "#0f0";
redIcon.path = baseSvg.x2;
redIcon.fillColor = "#f00";

var marker1 = new google.maps.Marker({
    position: markerPos,
    map: map,
    icon: greenIcon
});
var marker2 = new google.maps.Marker({
    position: markerPos, 
    map: map,
    icon: redIcon
});

显然没有优化js，但你明白了。

Answer 2

说到不透明度，strokeOpacity就是你的家伙。有关符号属性的详细信息，请查看maps.Symbol class。

多色Google Map SVG符号

2 个答案: