Question

我想在codeigniter中验证2个日期输入，条件是，如果结束日期大于开始日期，则会出现警告[javascript警告或某事]或无法输入数据

我的表格是这样的，

<h1><?php echo $title; ?></h1>
<form action="<?= base_url(); ?>index.php/admin/kalender/buat" method="post" enctype="multipart/form-data" name="form" id="form">
<?php
echo "<p><label for='IDKategori'>Tingkatan Pimpinan :</label><br/>";
echo form_dropdown('IDKategori', $kategori) . "</p>";

echo "<label for='ptitle'>Kegiatan / Lokasi :</label><br/>";
$data = array('class' => 'validate[required] text-input', 'name' => 'judul', 'id' => 'ptitle', 'size' => 80);
echo form_input($data);

echo "<p><label for='long'>Uraian Kegiatan / Keterangan / Catatan :</label><br/>";
$data = array('class' => 'validate[required] text-input', 'name' => 'konten', 'rows' => '13', 'cols' => '60', 'style' => 'width: 60%');
echo form_textarea($data) . "</p>";

echo "<p><label for='ptitle'>Waktu Mulai :</label><br/>";
$data = array('class' => 'validate[required] text-input', 'name' => 'TanggalMulai', 'id' => 'basic_example_1');
echo form_input($data) . "</p>";

echo "<p><label for='ptitle'>Waktu Akhir :</label><br/>";
$data = array('class' => 'validate[required] text-input', 'name' => 'TanggalAkhir', 'id' => 'basic_example_2');
echo form_input($data) . "</p>";

echo form_submit('submit', 'Tambah Even');
?>
&nbsp;&nbsp;<input type="button" value="Kembali" onClick="javascript: history.go(-1)" />

和我这样的javascript，

<script language="javascript" type="text/javascript">$(document).ready(function() {
    $.validator.addMethod("TanggalAkhir", function(value, element) {
        var startDate = $('.TanggalMulai').val();
        return Date.parse(startDate) <= Date.parse(value) || value == "";
    }, "* End date must be after start date");
    $('#form').validate();
});

为什么不工作？

Answer 1

您将输入作为类引用，但尚未定义类。由于您已经定义了id，为什么不以这种方式引用它：

var startDate = $('#basic_example_2').val();

验证startdate和enddate codeigniter

1 个答案: