我动态注册2个reciver以获取sms发送的结果和我的代码中的传递状态,我无法创建新类,这必须在现有类(扩展对话框)中完成。 我如何取消注册接收器。
我已经阅读了其他帖子并且没有帮助,他们要么有一个单独的类,要么他们在xml清单中注册接收器。
这是我的代码
private void sendSMS(String keyword, String msisdn) {
String SENT = "SMS_SENT";
String DELIVERED = "SMS_DELIVERED";
PendingIntent sentPI = PendingIntent.getBroadcast(mContext, 0,
new Intent(SENT), 0);
PendingIntent deliveredPI = PendingIntent.getBroadcast(mContext, 0,
new Intent(DELIVERED), 0);
mContext.registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode())
{
case Activity.RESULT_OK:
break;
case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
sendEventLog("Failed(Generic failure)");
break;
case SmsManager.RESULT_ERROR_NO_SERVICE:
sendEventLog("Failed(No service)");
break;
case SmsManager.RESULT_ERROR_NULL_PDU:
sendEventLog("Failed(Null PDU)");
break;
case SmsManager.RESULT_ERROR_RADIO_OFF:
sendEventLog("Failed(Radio off)");
break;
}
}
}, new IntentFilter(SENT));
//---when the SMS has been delivered---
mContext.registerReceiver(new BroadcastReceiver(){
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode())
{
case Activity.RESULT_OK:
break;
case Activity.RESULT_CANCELED:
sendEventLog("Failed(SMS not delivered)");
break;
}
}
}, new IntentFilter(DELIVERED));
SmsManager MySmsManager = SmsManager.getDefault();
MySmsManager.sendTextMessage(msisdn, null, keyword, sentPI, deliveredPI);
}
答案 0 :(得分:0)
您只需存储对您即时创建的接收器的引用。
BroadcastReceiver rcv;
rcv = new BroadcastReceiver() { ... }
mContext.registerReceiver(rcv);
使用此引用(rcv
),您可以取消注册它。
答案 1 :(得分:0)
您似乎除了跟踪接收器之外别无选择。
有关此主题,另请参阅Do I need to unregister 'anonymous' BroadcastReceiver。