Question

我有一个varchar变量，其内容如下：'123,12,7654321,9998 ...'。我在Oracle 10gR2中工作。如何实现以下输出格式？：

------
123
12
7654321
9998
...
------

谢谢！

Answer 1

试试这个

SELECT EXTRACTVALUE(COLUMN_VALUE,'text()') VALS 
FROM XMLTABLE('123,12,7654321,9998');

或

SELECT COLUMN_VALUE VALS FROM XMLTABLE('123,12,7654321,9998');

Answer 2

以下是使用connect的方法：

with str as (select '123,12,7654321,9998' as val from dual)
select cast(regexp_substr(val,'[^,]+', 1, level) as int)
from str
connect by cast(regexp_substr(val, '[^,]+', 1, level) as int) is not null;

我承认我从article改编了它。你要做的事情通常是放在一个叫做“拆分”的函数中。

Answer 3

试试这个：

/* Formatted on 1/30/2013 1:24:07 PM (QP5 v5.227.12220.39724) */
WITH val AS (SELECT '123,12,7654321,9998' txt FROM DUAL)
SELECT REGEXP_SUBSTR (txt,
              '[0-9]+|[a-z]+|[A-Z]+',
              1,
              lvl)
  FROM (SELECT txt,
           LEVEL lvl
      FROM val
    CONNECT BY LEVEL <=   LENGTH (txt)
                - LENGTH (REPLACE (txt,
                           ','))
                + 1)

从Oracle中的字符串变量中提取多个数字

3 个答案: