成功消息未显示,并且url未重定向到activate.php?success

时间:2013-01-31 14:54:29

标签: php

我很难弄清楚PHP用户/注册网站的错误。 注册后,会发送带有激活链接的电子邮件,当单击该链接时,它会成功激活该帐户,但不会显示成功消息。

如果我在浏览器中复制/粘贴激活链接并更改链接中的电子邮件或电子邮件代码中的字母,它将成功地向我提供所有错误消息。

激活链接如下所示:

http://website.com/activate.php?email=useremail@website.com&email_code=2631df446b129480abdbf54f08e8c494

这是我的activate.php的代码

<?php 
include 'core/init.php';
logged_in_redirect();
include 'includes/overall/header.php';
?>

<?php 
if (isset($_GET['success']) == true && empty($_GET['success']) == true) {
    ?>
<h3>Thanks, your account has been activated..</h3>
<p>You're free to log in!</p>
<?php
    header('Location: activate.php?success');
    exit();
} else if (isset($_GET['email'], $_GET['email_code']) === true) {

$email      = trim($_GET['email']);
$email_code = trim($_GET['email_code']);

if (email_exists($email) === false) {
    $errors[] = 'Ooops something went wrong, and we couldn\'t find that email adress!';
    } else if (activate($email, $email_code) === false) {
    $errors[] = 'We had problems activating your account';
    } if (empty($errors) === false) {
?>
    <h2>Ooops...</h2>
<?php
    echo output_errors($errors);
} else {
    header('Location: activate.php?success');
    exit();
}
} else {
header('Location: index.php');
exit();
}
?>

<?php include 'includes/overall/footer.php'; ?>

为什么它不会给我成功消息和重定向?

网址不会改变:http://website.com/activate.php?email=useremail@website.com&email_code=2631df446b129480abdbf54f08e8c494

于: website.com/activate.php?success

4 个答案:

答案 0 :(得分:0)

这条线有些可疑:

if (isset($_GET['success']) == true && empty($_GET['success']) == true) {

你确定它不是&& empty($_GET['success']) == false)吗?

答案 1 :(得分:0)

从不使用 HTML代码命令使用 HTMLcode&lt;?php PHPcode 语法。
基本上:您首先输出一个字符串(您的HTML代码),然后尝试输出标题 这是不正确的。标题需要在发送之前发送。你想要做的是将整个文档转换为PHP(文档的第一个字符应该是&lt;?php ),然后使用heredoc语法实际插入一段HTML代码,并且回显它们(所有收集到一个变量并在代码的最后一行回显)。避免将PHP与HTML混合,就像您在此处不惜一切代价一样。

答案 2 :(得分:0)

您将其设置为activate == true并将空重定向到该确切页面,以便获得重定向循环。

if (isset($_GET['success']) == true && empty($_GET['success']) == true) {
        header('Location: activate.php?success');
        exit();
}

尝试

if (isset($_GET['success']) == true && empty($_GET['success']) == true) {
       echo "It worked";
       exit();
}

答案 3 :(得分:0)

您应该测试哪些条件失败,请参阅下文。作为旁注:如果你没有通过状态,你不需要exit中的括号,你也不需要打开和关闭php这么多,没有必要:

<?php 
include 'core/init.php';
logged_in_redirect();
include 'includes/overall/header.php';

if (isset($_GET['success']) && !empty($_GET['success'])) {
    //in activate.php isset($_GET['success']) add this ouput, 
    //it works / not recommended and never seen.
    //echo "<h3>Thanks, your account has been activated..</h3>";
    //echo "<p>You're free to log in!</p>";
    header('Location: activate.php?success');
    exit;
} else if (isset($_GET['email'], $_GET['email_code'])) {
    $email = trim($_GET['email']);
    $email_code = trim($_GET['email_code']);
    if (email_exists($email) === false) {
        $errors[] = 'Ooops something went wrong, and we couldn\'t find that email adress!';
    } else if (activate($email, $email_code) === false) {
        $errors[] = 'We had problems activating your account';
    } if (empty($errors) === false) {
        echo "<h2>Ooops...</h2>";
        echo output_errors($errors);
    } else {
        header('Location: activate.php?success');
        exit;
    }
} else {
    // The following 2 lines: You should see 1, 0 or nothing
    // From there you should be able to troubleshoot.        
    echo "isset: ".isset($_GET['success'])."<br>";
    echo "Empty: ".empty($_GET['success']);
    //header('Location: index.php');
    exit;
}
include 'includes/overall/footer.php';

当我使用?success测试上述代码时,它会重定向我。

修改

如果我理解正确并且您在empty($_GET['success'] == true)内使用activate.php上面的代码,那么如果它有效,您将收到无限的标头重定向错误。您的逻辑需要重新审视。