Question

我有一个表korisnik有3列（id，用户名，密码）。我想要一些像：

$upit = "SELECT * FROM korisnik WHERE username = '" . $_POST['username'] . "'
AND password = SHA1('" . $_POST['password'] . "')";
$temp = $upit->fetch(PDO::FETCH_ASSOC); 
        $_SESSION['id'] = $temp['id'];

 if ($pdo_izraz->num_rows() == 1) {    
    session_start();
    $_SESSION['autorizovan'] = 1;
    $temp = $pdo_izraz->fetch(PDO::FETCH_ASSOC);
    $_SESSION['id'] = $temp['id'];

    $upit = ("Select * from korisnici where id=" . $_SESSION['id']);*
    $izraz = $dbh->query($upit);
    $obj = $izraz->fetch(PDO::FETCH_ASSOC);
    $username = $obj['username'];
    echo "<p id='bbb'><b >$username</b>:Welcome</p>";

我想在CodeIgniter中执行类似的操作（获取一行，其中id =一行数组（$ _SESSION ['id']

Answer 1

我认为您正在寻找result_array()

请参阅手册here

$query = $this->db->query("YOUR QUERY");

foreach ($query->result_array() as $row)
{
   echo $row['title'];
   echo $row['name'];
   echo $row['body'];
}

<强>更新

public function login($user, $pass) // Takeing the username/pass from form
{
    $this->db->where('username', $user);
    $this->db->where('password', md5($pass));

    $query = $this->db->get('korisnici');

    if ($query->num_rows() == 1)
    {
        $_SESSION['id'] = $this->query->row()->id;
        return TRUE;
    }
    else
    {
        return FALSE;
    }
}

public function getData()//Get result of array
{
    $this->db->where('id', $_SESSION['id']);
    $query = $this->db->get('korisnici');
    return $query->result(); // here you can change for result_array() if you want
}

CodeIgniter - 从表获取行，其中id是数组的id

1 个答案: