Question

我有一个名为ipcam (camera id,camera name,camera model,IP address, Url, Port)的表。我成功地从MySQL数据库中检索数据。现在我打算做的是在最后一个名为Delete的表中添加一个额外的字段 - 这是超链接并通过向deletecam.php页面发送id删除该行，这里是代码：

<?php                               
$result = mysql_query("SELECT * from ipcam WHERE user_id = {$user_id}");
echo"<table border=5 colspan=6> <tr><th>IP CAMERA ID &nbsp;&nbsp;</th><th>IP CAMERA NAME &nbsp;&nbsp;</th><th>CAMERA MODEL&nbsp;&nbsp;</th> <th>IP ADDRESS&nbsp;&nbsp;</th> <th>URL&nbsp;&nbsp;</th> <th>PORT&nbsp;&nbsp;</th><th>DELETE&nbsp;&nbsp;</th></tr>";
while($row = mysql_fetch_array($result)){
    echo "<tr>
    <td>" . $row['id'] . "</td>
    <td>" . $row['name'] . "</td>
    <td>" . $row['model'] . "</td>
    <td>" . $row['ipaddress'] . "</td>
    <td>" . $row['url'] . "</td>
    <td>" . $row['port'] . "</td>      
    <td> echo"<html><h3>"; <a href="/deletecam.php?id= <?php echo urlencode($row['id']); ?> "> Delete </a>  echo"</h3></html>"; </td></tr>"; 

}
echo "</table>";
?>

但是，当我运行此代码时，我遇到了一个奇怪的问题，错误是：

Parse error: syntax error, unexpected '>' in C:\xampp\htdocs\IPCAM\cameralist.php on line 176

当我尝试在代码中包含超链接时，错误来自删除。我做错了语法或者不可能做这样的事情。

Answer 1

试试这个，你不应该得到一个错误。你没有结束回声字符串。

 <?php 

    $result = mysql_query("SELECT * from ipcam WHERE user_id = {$user_id}");


    echo"<table border=5 colspan=6> <tr><th>IP CAMERA ID &nbsp;&nbsp;</th><th>IP CAMERA NAME &nbsp;&nbsp;</th><th>CAMERA MODEL&nbsp;&nbsp;</th> <th>IP ADDRESS&nbsp;&nbsp;</th> <th>URL&nbsp;&nbsp;</th> <th>PORT&nbsp;&nbsp;</th><th>DELETE&nbsp;&nbsp;</th></tr>";

    while($row = mysql_fetch_array($result))
    {

    echo "<tr>
    <td>" . $row['id'] . "</td>
    <td>" . $row['name'] . "</td>
    <td>" . $row['model'] . "</td>
    <td>" . $row['ipaddress'] . "</td>
    <td>" . $row['url'] . "</td>
    <td>" . $row['port'] . "</td>"  ; // i missed a " here
    ?>
    <td> <h3><a href="/deletecam.php?id= <?php echo urlencode($row['id']); ?> "> Delete </a>  </h3></td></tr> 

    <?php
            }

    echo "</table>";
?>

Answer 2

将其更改为：

while ($row = mysql_fetch_array($result)) {
    echo "<tr>
    <td>" . $row['id'] . "</td>
    <td>" . $row['name'] . "</td>
    <td>" . $row['model'] . "</td>
    <td>" . $row['ipaddress'] . "</td>
    <td>" . $row['url'] . "</td>
    <td>" . $row['port'] . "</td>      
    <td> <h3> <a href='/deletecam.php?id=" . urlencode($row['id']) . "'> Delete </a> </h3> </td></tr>"; 
}

表格中不应该有<html>。并且您不能在回显的字符串中使用<?php。

无法向重复表添加超链接

2 个答案: