Question

我想基于给定的IPv6地址更新djbdns（dbndns）配置文件，例如： 2a01:488:66:1000:523:f116:0:1或::1。

dbndns需要扩展的IPv6地址，例如2a010488006610000523f11600000001的{{1}}。

扩展此类IPv6地址的最简单方法是什么？

Answer 1

使用sipcalc可能会这样做。它提供的信息比您需要的多，但有点grep和cut可以解决这个问题： - ）

$ EXPANDED=`sipcalc 2001::1 | fgrep Expanded | cut -d '-' -f 2`
$ echo $EXPAND
2001:0000:0000:0000:0000:0000:0000:0001

供参考，这是sipcalc的完整输出：

$ sipcalc 2001::1
-[ipv6 : 2001::1] - 0

[IPV6 INFO]
Expanded Address        - 2001:0000:0000:0000:0000:0000:0000:0001
Compressed address      - 2001::1
Subnet prefix (masked)  - 2001:0:0:0:0:0:0:1/128
Address ID (masked)     - 0:0:0:0:0:0:0:0/128
Prefix address          - ffff:ffff:ffff:ffff:ffff:ffff:ffff:ffff
Prefix length           - 128
Address type            - Aggregatable Global Unicast Addresses
Network range           - 2001:0000:0000:0000:0000:0000:0000:0001 -
                          2001:0000:0000:0000:0000:0000:0000:0001

Answer 2

我最近想要一种可以跨shell移植并在openwrt等平台上工作的无依赖解决方案。我想出了以下片段：

# helper to convert hex to dec (portable version)
hex2dec(){
    [ "$1" != "" ] && printf "%d" "$(( 0x$1 ))"
}

# expand an ipv6 address
expand_ipv6() {
    ip=$1

    # prepend 0 if we start with :
    echo $ip | grep -qs "^:" && ip="0${ip}"

    # expand ::
    if echo $ip | grep -qs "::"; then
        colons=$(echo $ip | sed 's/[^:]//g')
        missing=$(echo ":::::::::" | sed "s/$colons//")
        expanded=$(echo $missing | sed 's/:/:0/g')
        ip=$(echo $ip | sed "s/::/$expanded/")
    fi

    blocks=$(echo $ip | grep -o "[0-9a-f]\+")
    set $blocks

    printf "%04x:%04x:%04x:%04x:%04x:%04x:%04x:%04x\n" \
        $(hex2dec $1) \
        $(hex2dec $2) \
        $(hex2dec $3) \
        $(hex2dec $4) \
        $(hex2dec $5) \
        $(hex2dec $6) \
        $(hex2dec $7) \
        $(hex2dec $8)
}

我也有这个功能来压缩

# returns a compressed ipv6 address under the form recommended by RFC5952
compress_ipv6() {
    ip=$1

    blocks=$(echo $ip | grep -o "[0-9a-f]\+")
    set $blocks

    # compress leading zeros
    ip=$(printf "%x:%x:%x:%x:%x:%x:%x:%x\n" \
        $(hex2dec $1) \
        $(hex2dec $2) \
        $(hex2dec $3) \
        $(hex2dec $4) \
        $(hex2dec $5) \
        $(hex2dec $6) \
        $(hex2dec $7) \
        $(hex2dec $8)
    )

    # prepend : for easier matching
    ip=:$ip

    # :: must compress the longest chain
    for pattern in :0:0:0:0:0:0:0:0 \
            :0:0:0:0:0:0:0 \
            :0:0:0:0:0:0 \
            :0:0:0:0:0 \
            :0:0:0:0 \
            :0:0; do
        if echo $ip | grep -qs $pattern; then
            ip=$(echo $ip | sed "s/$pattern/::/")
            # if the substitution occured before the end, we have :::
            ip=$(echo $ip | sed 's/:::/::/')
            break # only one substitution
        fi
    done

    # remove prepending : if necessary
    echo $ip | grep -qs "^:[^:]" && ip=$(echo $ip | sed 's/://')

    echo $ip
}

您可以将它们组合起来测试给定输入是否为ipv6

# a valid ipv6 is either the expanded form or the compressed one
is_ipv6(){
    expanded="$(expand_ipv6 $1)"
    [ "$1" = "$expanded" ] && return 0
    compressed="$(compress_ipv6 $expanded)"
    [ "$1" = "$compressed" ] && return 0
    return 1
}

我希望这有帮助！这些片段取自https://github.com/chmduquesne/wg-ip。如果您发现任何错误，请提供帮助！

Answer 3

这对你好吗？

kent$  echo "2a01:488:66:1000:523:f116:0:1"|awk -F: '{for(i=1;i<=NF;i++)x=x""sprintf ("%4s", $i);gsub(/ /,"0",x);print x}'
2a010488006610000523f11600000001

在shell脚本中展开ipv6地址

3 个答案: