我之前已成功使用java -classpath
通配符扩展功能。我目前遇到了一个奇怪的问题。
通配符应该扩展到指定文件夹中的每个jar
。以下是Oracle的一句话:
Class path entries can contain the basename wildcard character *,
which is considered equivalent to specifying a list of all the files
in the directory with the extension .jar or .JAR. For example, the
class path entry foo/* specifies all JAR files in the directory
named foo. A classpath entry consisting simply of * expands to a
list of all the jar files in the current directory.
This is a link to Oracle doc on Java 6 on the subject of classpath.
我看到的行为与此相矛盾。这是3次运行。第一个明确地命名jar
,因此它起作用。其他人使用通配符并失败。为什么?这对我来说很重要,因为我依赖通配符(其他地方),所以对这种意外行为的理解对我来说很重要。
#!/bin/bash
printf "The EV is...\n"
echo $CLASSPATH
printf "The working directory is...\n"
pwd
printf "Directory listing...\n"
ls
printf "END of directory listing.\n"
printf "Test with named jar.\n"
java -javaagent:../sizeof/sizeof.jar -classpath ./testsizeof.jar info.zqxj.test.Tester
printf "Test with star.\n"
java -javaagent:../sizeof/sizeof.jar -classpath * info.zqxj.test.Tester
printf "Test with dot slash star.\n"
java -javaagent:../sizeof/sizeof.jar -classpath ./* info.zqxj.test.Tester
输出:
The EV is...
The working directory is...
/home/b/Documents/workspace/testsizeof
Directory listing...
bin run.sh src testsizeof.jar
END of directory listing.
Test with named jar.
40
Test with star.
Exception in thread "main" java.lang.NoClassDefFoundError: run/sh
Caused by: java.lang.ClassNotFoundException: run.sh
at java.net.URLClassLoader$1.run(URLClassLoader.java:202)
at java.security.AccessController.doPrivileged(Native Method)
at java.net.URLClassLoader.findClass(URLClassLoader.java:190)
at java.lang.ClassLoader.loadClass(ClassLoader.java:306)
at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301)
at java.lang.ClassLoader.loadClass(ClassLoader.java:247)
Could not find the main class: run.sh. Program will exit.
Test with dot slash star.
Exception in thread "main" java.lang.NoClassDefFoundError: //run/sh
Caused by: java.lang.ClassNotFoundException: ..run.sh
at java.net.URLClassLoader$1.run(URLClassLoader.java:202)
at java.security.AccessController.doPrivileged(Native Method)
at java.net.URLClassLoader.findClass(URLClassLoader.java:190)
at java.lang.ClassLoader.loadClass(ClassLoader.java:306)
at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301)
at java.lang.ClassLoader.loadClass(ClassLoader.java:247)
Could not find the main class: ./run.sh. Program will exit.
答案 0 :(得分:6)
解决方案,双引号classpath参数。示例:-classpath "*"
这在命令行和bash脚本中都是必需的。
随后的附录:
此外,请注意-classpath "~/folder/*"
失败,但-classpath ~/folder/"*"
是好的。引用通配符但不引用~
。您似乎需要操作系统来解释~
,但您需要引用*
通配符,因为您希望将其传递给java
以便以Java方式进行扩展。
另请注意,您不应要求java
展开*.jar
,因为这会产生意想不到的结果。 Java规范说正确的通配符只是*
。