mysql now()列的日期时间值不正确 - 错误代码1292

时间:2009-09-25 09:20:20

标签: mysql warnings

使用now()...

进行简单的数学运算时
    mysql> 
select cdrstatuschangets from cdrs where ( cdrstatuschangets < now() - 10 );
    +---------------------+
    | cdrstatuschangets   |
    +---------------------+
    | 2009-09-25 13:55:50 |
    +---------------------+
    1 row in set (0.00 sec)

    show warnings;
    Empty set (0.00 sec)

它经常奏效,但有时候......

    mysql> 
select cdrstatuschangets from cdrs where ( cdrstatuschangets < now() - 50 );
    +---------------------+
    | cdrstatuschangets   |
    +---------------------+
    | 2009-09-25 13:55:50 |
    +---------------------+
    1 row in set, 1 warning (0.00 sec)


show warnings;
+---------+------+-----------------------------------------------------------------------+
| Level   | Code | Message |                                                                                  |
+---------+------+-----------------------------------------------------------------------+
| Warning | 1292 | Incorrect datetime value: '20090925211564.000000' for column 'cdrStatusChangeTS' at row 1 |
+---------+------+-----------------------------------------------------------------------+
1 row in set (0.00 sec)

尽管有预期,但有时候不会给出选择结果。

2 个答案:

答案 0 :(得分:4)

使用now()进行简单的数学运算存在一个阴险的问题...秒和分钟的减法等基于一分钟100秒,一小时100分钟......

有时似乎有效,有时却没有。阴险。

mysql> select now(); select now() -10;
+---------------------+
| now()               |
+---------------------+
| 2009-09-25 21:07:20 |
+---------------------+
1 row in set (0.00 sec)

+-----------------------+
| now() -10             |
+-----------------------+
| 20090925210710.000000 |
+-----------------------+
1 row in set (0.00 sec)

一切都很好,但是......

mysql> select now(); select now() -10;
+---------------------+
| now()               |
+---------------------+
| 2009-09-25 21:08:02 |
+---------------------+
1 row in set (0.00 sec)

+-----------------------+
| now() -10             |
+-----------------------+
| 20090925210792.000000 |
+-----------------------+
1 row in set (0.00 sec)

显示92秒的时间戳(看起来像时间戳)。

原来我需要做更像

的事情
select cdrstatuschangets from cdrs where ( cdrstatuschangets < now() - INTERVAL 50 SECOND );

但这是“伤害”问题的间歇性特征。

答案 1 :(得分:1)

我建议使用DateAdd代替可靠性和可读性。

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