Question

我有一张桌子

'310', 'D', '1', '0', 'Clowns.jpg', ?, '63527560196'
'311', 'D', '1', '1', 'Clowns_102_x_102.jpg', ?, '63527560197'
'312', 'D', '1', '1', 'Clowns_45_x_45.jpg', ?, '63527560197'
'313', 'D', '1', '1', 'Clowns_80_x_80.jpg', ?, '63527560197'
'314', 'D', '1', '1', 'Clowns_120_x_120.jpg', ?, '63527560198'
'315', 'D', '1', '1', 'Clowns_180_x_180.jpg', ?, '63527560198'
'316', 'D', '1', '1', 'Clowns_300_x_300.jpg', ?, '63527560198'

我想将名为Clowns的文件重命名为Clowning，因此数据看起来像这样

'310', 'D', '1', '0', 'Clowning.jpg', ?, '63527560196'
'311', 'D', '1', '1', 'Clowning_102_x_102.jpg', ?, '63527560197'
'312', 'D', '1', '1', 'Clowning_45_x_45.jpg', ?, '63527560197'
'313', 'D', '1', '1', 'Clowning_80_x_80.jpg', ?, '63527560197'
'314', 'D', '1', '1', 'Clowning_120_x_120.jpg', ?, '63527560198'
'315', 'D', '1', '1', 'Clowning_180_x_180.jpg', ?, '63527560198'
'316', 'D', '1', '1', 'Clowning_300_x_300.jpg', ?, '63527560198'

所以我试过这个

UPDATE new_images 
SET 
filespec = 'clowns100' + MID(filespec, 7, LENGTH(filespec) - 6);

但是我得到了

错误代码：1292。截断错误的DOUBLE值：'clowns100'

Answer 1

使用REPLACE

UPDATE new_images SET filespec = REPLACE(filespec, 'Clowns','Clowning')

MySQL Replace (String Function)

更新1

您查询的等效mysql代码是

UPDATE new_images 
SET filespec = CONCAT('clowns100', MID(filespec, 7, CHAR_LENGTH(filespec) - 6));

Answer 2

您可以在SQL中使用子字符串

 UPDATE new_images SET filespec = 'Clowning'+substring('Clowns.jpg', 7, len('Clowns.jpg') - 6) where filespec like 'Clowns%'

重命名表中的文件名

2 个答案: