Question

我正在尝试创建一个简单的喜欢/不同的按钮来更新数据库。 jQuery代码位于外部文件中。 PHP变量从Codeigniter中的控制器发送。

当页面加载新鲜时，它会正确显示当前登录的用户是否能够喜欢或与他们正在查看的用户不同。如果他们点击一次，一切都按预期工作 - 按钮在Like / Different之间切换，喜欢的数量增加或减少，数据库更新。在第二次单击时，它会重新加载整个页面，但不会更新数据库 - 如何在不重新加载页面的情况下停止刷新+更新？

PHP：

<div id="like_button">

<p><a href=""><span id="like_unlike" class="link"><?php if($already_liked){echo "Unlike";}else{echo"Like";}?></span></a> (<span id="number_of_likes"><?php echo $number_of_likes; ?></span>)</p>

<span id="liked_unliked_user_id" style="display:none"><?php echo $liked_unliked_user_id; ?></span>
<span id="liking_unliking_user_id" style="display:none"><?php echo $liking_unliking_user_id; ?></span>

</div>

jQuery：

$( function() {

$( '#like_button a' ).click( function( e ) {

  var thisrecord = $( this ).closest( "div" );

  var liking_unliking_user_id = parseInt( thisrecord.find( "span#liking_unliking_user_id" ).html() );
  var liked_unliked_user_id = parseInt( thisrecord.find( "span#liked_unliked_user_id" ).html() );
  var like_unlike = thisrecord.find( "#like_unlike" ).html();


  if (like_unlike == 'Like') 
  {
    $( this ).replaceWith( '<a href=""><span id="like_unlike" class="link">Unlike</span></a>' );
    var likes = parseInt( thisrecord.find( "span#number_of_likes" ).html() ) + 1;
    thisrecord.find( "span#number_of_likes" ).html( likes );
    $.post( base_url+"/controller/function/" + liked_unliked_user_id + "/" + liking_unliking_user_id );
  }
  else
  {
    $( this ).replaceWith( '<a href=""><span id="like_unlike" class="link">Like</span></a>' );
    var likes = parseInt( thisrecord.find( "span#number_of_likes" ).html() ) - 1;
    thisrecord.find( "span#number_of_likes" ).html( likes );
    $.post( base_url+"/controller/function/" + liked_unliked_user_id + "/" + liking_unliking_user_id );
  }

  e.preventDefault();
});
});

Answer 1

当您第一次创建.click()事件时，jQuery选择器会找到所有'#like_button a'元素并将此事件附加到它们。当您使用#like_button a替换$(this).replaceWith(...)元素时，此新元素会附加.click()事件，因为您的原始选择器仅运行一次以附加事件（此时此元素不存在）。

在您的代码中，页面会重新加载，因为您点击的链接只是链接回当前页面 - .click()函数阻止e.preventDefault()的事件。

如果您命名该函数，然后在替换对象后重新附加.click()事件，则该函数应该正常运行：

$( function() {
    function toggleLike(e)
    {
        var thisrecord = $( this ).closest( "div" );

        var liking_unliking_user_id = parseInt( thisrecord.find( "span#liking_unliking_user_id" ).html() );
        var liked_unliked_user_id = parseInt( thisrecord.find( "span#liked_unliked_user_id" ).html() );
        var like_unlike = thisrecord.find( "#like_unlike" ).html();


        if (like_unlike == 'Like') 
        {
            $( this ).replaceWith( '<a href=""><span id="like_unlike" class="link">Unlike</span></a>' );
            var likes = parseInt( thisrecord.find( "span#number_of_likes" ).html() ) + 1;
            thisrecord.find( "span#number_of_likes" ).html( likes );
            $( '#like_button a' ).click(toggleLike); // **frakenstein teh .click() event
            $.post( base_url+"/controller/function/" + liked_unliked_user_id + "/" + liking_unliking_user_id );
        } else {
            $( this ).replaceWith( '<a href=""><span id="like_unlike" class="link">Like</span></a>' );
            var likes = parseInt( thisrecord.find( "span#number_of_likes" ).html() ) - 1;
            thisrecord.find( "span#number_of_likes" ).html( likes );
            $( '#like_button a' ).click(toggleLike); // **frakenstein teh .click() event
            $.post( base_url+"/controller/function/" + liked_unliked_user_id + "/" + liking_unliking_user_id );
        }

        e.preventDefault();
    }

    $( '#like_button a' ).click(toggleLike);
});

jQuery / PHP喜欢/不像Button

1 个答案: