我有一个JSON对象数组，我想从中创建一个＆＃34;单个JavaScript对象。＆＃34;我很欣赏Python或JavaScript中的想法。事实上，我甚至不确定描述（或谷歌）这类问题的正确术语是什么。谢谢！
原始列表如下所示：
[
{
"State_Code": "01",
"County_Code": "000",
"State_Abbrv": "AL",
"County_Name": "ALABAMA",
"DATA": "12345"
},
{
"State_Code": "01",
"County_Code": "001",
"State_Abbrv": "AL",
"County_Name": "AUTAUGA COUNTY",
"DATA": "123"
},
{
"State_Code": "01",
"County_Code": "003",
"State_Abbrv": "AL",
"County_Name": "BALDWIN COUNTY",
"DATA": "321"
},
{
"State_Code": "02",
"County_Code": "000",
"State_Abbrv": "AK",
"County_Name": "ALASKA",
"DATA": "98765"
},
{
"State_Code": "02",
"County_Code": "013",
"State_Abbrv": "AK",
"County_Name": "ALEUTIANS EAST BOROU",
"DATA": "456"
},
.............. ]
我希望它看起来像这样：
{
"name": "USA",
"children": [
{
"name": "ALABAMA",
"children": [
{
"name": "AUTAUGA COUNTY",
"DATA": 123
},
{
"name": "BALDWIN COUNTY",
"DATA": 321
}
]
},
{
"name": "ALASKA",
"children": [
{
"name": "ALEUTIANS EAST BOROU",
"DATA": 456
}
]
}
.............
]
}
我试图像这样的想法使用Python循环（对于任何拼写错误道歉，今晚会修复）：
runningListCounty = []
tempD = defaultdict(dict)
tempDCounty = defaultdict(dict)
i = 0
for l in listOfJson:
if l['County_Code'] == '000'
tempD['name'] = l['County_Name']
if i > 0: #only do this after the first loop
tempD['children'] = runningListCounty
runningList.append(tempD)
runningListCounty = []
tempD = defaultdict(dict)
else:
tempDCounty = defaultdict(dict)
tempDCounty['name'] = l['County_Name']
tempDCounty['DATA'] = l['DATA']
runningListCounty.append(tempDCounty)
i = i + 1
答案 0 :(得分：0)
尝试使用猜测工作。
data = [
{
"State_Code": "01",
"County_Code": "000",
"State_Abbrv": "AL",
"County_Name": "ALABAMA",
"DATA": "12345"
},
{
"State_Code": "01",
"County_Code": "001",
"State_Abbrv": "AL",
"County_Name": "AUTAUGA COUNTY",
"DATA": "123"
},
{
"State_Code": "01",
"County_Code": "003",
"State_Abbrv": "AL",
"County_Name": "BALDWIN COUNTY",
"DATA": "321"
},
{
"State_Code": "02",
"County_Code": "000",
"State_Abbrv": "AK",
"County_Name": "ALASKA",
"DATA": "98765"
},
{
"State_Code": "02",
"County_Code": "013",
"State_Abbrv": "AK",
"County_Name": "ALEUTIANS EAST BOROU",
"DATA": "456"
}
]
roots = [ d for d in data if d['County_Code'] == '000']
def crawl(data, roots):
for root in roots:
yield {
'name' : root['County_Name'],
'children' : [{ 'name' : d['County_Name'], 'DATA' : d['DATA'] }
for d in data if d['County_Code'] != '000' and d['State_Code'] == root['State_Code']]
}
final = { 'name' : 'USA', 'children' : [ x for x in crawl(data, roots)]}
import pprint
pprint.pprint(final)
给出：
{'children': [{'children': [{'DATA': '123', 'name': 'AUTAUGA COUNTY'},
{'DATA': '321', 'name': 'BALDWIN COUNTY'}],
'name': 'ALABAMA'},
{'children': [{'DATA': '456', 'name': 'ALEUTIANS EAST BOROU'}],
'name': 'ALASKA'}],
'name': 'USA'}
答案 1 :(得分：0)
Javascript解决方案：
<强> Demo
var data = [
{
"State_Code": "01",
"County_Code": "000",
"State_Abbrv": "AL",
"County_Name": "ALABAMA",
"DATA": "12345"
},
{
"State_Code": "01",
"County_Code": "001",
"State_Abbrv": "AL",
"County_Name": "AUTAUGA COUNTY",
"DATA": "123"
},
{
"State_Code": "01",
"County_Code": "003",
"State_Abbrv": "AL",
"County_Name": "BALDWIN COUNTY",
"DATA": "321"
},
{
"State_Code": "02",
"County_Code": "000",
"State_Abbrv": "AK",
"County_Name": "ALASKA",
"DATA": "98765"
},
{
"State_Code": "02",
"County_Code": "013",
"State_Abbrv": "AK",
"County_Name": "ALEUTIANS EAST BOROU",
"DATA": "456"
}
];
var newData = { name : 'USA', children : [] };
for(var i=0; i<data.length; i++) {
if(data[i].County_Code == "000") {
newData.children.push({ name : data[i].County_Name, state_code : data[i].State_Code, children : [] });
}
}
for(var i=0; i<data.length; i++) {
if(data[i].County_Code != "000") {
for(var x=0; x<newData.children.length; x++) {
if(data[i].State_Code == newData.children[x].state_code) {
newData.children[x].children.push({ name : data[i].County_Name, data : data[i].DATA });
}
}
}
}
console.log(newData); // or convert to JSON with JSON.stringify(newData)
结果newData是：
{
"name": "USA",
"children": [
{
"name": "ALABAMA",
"state_code": "01",
"children": [
{
"name": "AUTAUGA COUNTY",
"data": "123"
},
{
"name": "BALDWIN COUNTY",
"data": "321"
}
]
},
{
"name": "ALASKA",
"state_code": "02",
"children": [
{
"name": "ALEUTIANS EAST BOROU",
"data": "456"
}
]
}
]
}
答案 2 :(得分：-1)
这是小提琴： 的 JSFIDDLE
以下是代码：
var statesObj = JsonSource,
finalObj = {
USA : {
name: "USA",
children: []
}
};
for (var st = 0; st < statesObj.length; ++st) {
// First the states
if( statesObj[st].County_Code === "000") {
var newState = {
name: statesObj[st].County_Name,
abbrv: statesObj[st].State_Abbrv,
children: []
};
finalObj.USA.children.push(newState);
}
}
for (var st = 0; st < statesObj.length; ++st) {
// Now the rest
if( statesObj[st].County_Code !== "000") {
var newChild = {
name: statesObj[st].County_Name,
data: statesObj[st].DATA
};
for (var sub in finalObj.USA.children) {
if (finalObj.USA.children.hasOwnProperty(sub) &&
finalObj.USA.children[sub].abbrv === statesObj[st].State_Abbrv) {
finalObj.USA.children[sub].children.push(newChild);
break;
}
}
}
}
var finalJson = JSON.stringify(finalObj);
console.log(finalJson);