Question

我最近已经开始重写我开始创建的重写参数处理代码，并且我添加了动态内存管理函数（malloc，realloc，free）的使用，但是在添加之后我尝试执行时遇到了奇怪的崩溃一个例子。

以下是我的程序输出：

charles @draton-generico：〜/ Documents / C / C89 / SDL_Work / 2D-game-base $ ./game-base-02-alt-2 --l

成功退出参数捕获循环。

==＆gt;继续执行。

*检测到glibc ./game-base-02-alt-2：realloc（）：下一个尺寸无效：0x000000000157c010 * *

输出这么多之后它就会挂起。

以下是我的代码：

/* 
 * CREATED BY:  Charles Edwin Swain 3rd
 * DATE OF PROJECT BEGINNING:  28/1/2013
 */

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv)
{
int* bse = malloc(3 + 5 + 5 + argc);
if (bse == NULL)
{
    if (fprintf(stderr, "Call to malloc failed, bse = NULL.\n==>Will now exit.\n") <= 0) exit(-2);
    exit(-1);
}
*(bse + 0) = 0;
while (*(bse + 0) < (3 + 5 + 5 + argc))
{
    *(bse + *(bse + 0)) = 0;
    *(bse + 0) = *(bse + 0) + 1;
}
*(bse + 0) = 0;
*(bse + 1) = -1;
/*THIS DETERMINES THE SIZE OF THE LARGEST ARGV CHARACTER STRING.*/
while (*(bse + 3) < argc)
{
    while (*(bse + 4) != -1)
    {
        if (argv[*(bse + 3)][*(bse + 4)] == '\0')
        {
            if ((*(bse + 4) + 1) > *(bse + 5)) *(bse + 5) = *(bse + 4) + 1;
            *(bse + 4) = -1;
        }
        else if (*(bse + 4) == 32766)
        {
            *(bse + 3 + 5 + 5 + *(bse + 3)) = 1;
            *(bse + 4) = -1;
        }
        else *(bse + 4) = *(bse + 4) + 1;
    }
    *(bse + 3) = *(bse + 3) + 1;
    *(bse + 4) = 0;
}
*(bse + 3) = 0;
/*ENSURING THAT SPACE FOR RETREIVED ARGV CHARACTER STRINGS IS AT LEAST THE SIZE OF THE LARGEST CHECKED FOR SPECIFIC STRING ON LINE BELOW.*/
if (*(bse + 5) < 10) *(bse + 5) = 10;
/*THIS IS (IN SOME CASES WAS) THE BIG ARGV CATCHING LOOP.*/
/*ERASED CONTENTS OF, AM REWRITING CODE.*/
while (*(bse + 3) < argc)
{
    *(bse + 3) = argc;
}
if (fprintf(stdout, "Successfully exited argument catching loop.\n==>Continuing execution.\n") <= 0)
{
    while ((*(bse + 1) <= 0)&&(*(bse + 2) < 50))
    {
        *(bse + 1) = fprintf(stderr, "A function (fprintf) failed when outputting a notification informing of having 'properly' left the argument catching loop.\n==>Will now exit.\n");
        *(bse + 2) = *(bse + 2) + 1;
    }
    free(bse);
    exit(-1);
}

/*SET DEFAULTS HERE*/

bse = realloc(bse, 3);
if (bse == NULL)
{
    if (fprintf(stderr, "Call to realloc failed, bse = NULL.\n==>Will now exit.\n") <= 0) exit(-2);
    exit(-1);
}

/*END OF CODE.*/
free(bse);
exit(0);
}

我很想把它变成一种学习经历。

Answer 1

malloc()和realloc()不知道您要将哪种数据类型存储在返回指针所指向的内存中。所以他们只是分配一些字节 - 并且他们不会将他们的参数神奇地乘以sizeof(int)。所以你想要的是：

int *bse = malloc((3 + 5 + 5 + argc) * sizeof(*bse));

和realloc()一样。

使用动态内存管理功能导致崩溃

1 个答案: