序列化OrientDB RecordID时无限递归

时间:2013-02-12 15:20:20

标签: java jackson orientdb

在我的架构中,我有一个这样的抽象类:

@JsonAutoDetect(JsonMethod.NONE)
public abstract class AbstractEntity {

    @Id private Object id;
    @Version private Integer version;

    public AbstractEntity() {}

    @JsonProperty // this annotation causes infinite recursion
    public Object getId() { return id; }

}

此类用作每个实体的超类,例如:

@JsonAutoDetect(JsonMethod.NONE)
public class Usuario extends AbstractEntity {

    private Cadastro cadastro;

    protected Usuario() {}

    public Usuario(Cadastro cadastro) {
        setCadastro(cadastro);
    }

    @JsonProperty
    public Cadastro getCadastro() { return cadastro; }

    @JsonProperty
    public void setCadastro(Cadastro cadastro) { this.cadastro = cadastro; }

}

我正在设计一个REST层,让用户通过JSON请求/响应在db中创建记录:

@POST
@Path("cadastrar")
@Consumes(MediaType.APPLICATION_JSON)
@Produces(MediaType.APPLICATION_JSON)
public Response cadastrar(@Context HttpServletRequest request, Cadastro cadastro) {
    OObjectDatabaseTx bd = (OObjectDatabaseTx) request.getAttribute("object.database.tx");

    try {

        bd.begin();
        Usuario usuario = new Usuario(cadastro);
        usuario = bd.save(usuario);
        bd.commit();

        String json = new ObjectMapper().writeValueAsString(usuario);
        Response response = Response.status(HttpURLConnection.HTTP_CREATED).entity(json).build();

        return response;
        (...)

然而,在最后一种方法中,当我调用Jackson来序列化我新创建的实体时(在writeValueAsString方法中),我得到一个无限递归:

org.codehaus.jackson.map.JsonMappingException: Infinite recursion (StackOverflowError) (through reference chain:
  com.orientechnologies.orient.core.id.ORecordId["record"]->com.orientechnologies.orient.core.record.impl.ODocument["identity"]
->com.orientechnologies.orient.core.id.ORecordId["record"]->com.orientechnologies.orient.core.record.impl.ODocument["identity"]
->com.orientechnologies.orient.core.id.ORecordId["record"]->com.orientechnologies.orient.core.record.impl.ODoc...

我可以通过从@JsonProperty类中的getId方法中删除AbstractEntity来避免无限递归。但是,这样JSON响应中不会出现id属性。

那么,如何序列化id属性?

谢谢!

1 个答案:

答案 0 :(得分:2)

杰克逊是否支持循环引用?是这样的吗?

相关问题