将ArrayList值动态传递给其他ArrayList

时间:2013-02-14 11:13:52

标签: java android arraylist

我有四个相同长度的数组(比如array1,array2 .... array4),我想动态地将这些数组的值传递给example array,这样我就可以添加条件并相应地获取值。我该怎么做?

   public SectionListItem[] exampleArray = { // Comment to prevent re-format
           new SectionListItem("array1 data","array2 data","array3 data", "array4 data")

    };

    private StandardArrayAdapter arrayAdapter;
    private SectionListAdapter sectionAdapter;
    private SectionListView listView;


    @Override
    public void onCreate(final Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        arrayAdapter = new StandardArrayAdapter(this, R.id.example_text_view, exampleArray);
        sectionAdapter = new SectionListAdapter(getLayoutInflater(), arrayAdapter);

        listView = (SectionListView) findViewById(android.R.id.list);



        setListAdapter(sectionAdapter);
        listView.setAdapter(sectionAdapter);



    }

1 个答案:

答案 0 :(得分:0)

这是一个简单的例子:

public class array3 {
    public static void main(String[] args) {
        int ar3[]={33,45,67,87,34,56};
        int ar4[]={5,8,9,22,3,4};
        List list1=new ArrayList();
        List list2=new ArrayList();
         for (int i = 0; i < ar3.length; i++) {
            list1.add(ar3[i]);
        }
   for (int i = 0; i < ar4.length; i++) {
            list2.add(ar4[i]);
        }
        list1.addAll(list2);
        System.out.println(list);           
    }
}