Question

我有以下代码：

try:
    while 1:
        s=socket.socket(socket.AF_INET,socket.SOCK_STREAM)
        s.settimeout(5);
        s.connect((HOST,PORT))
        print("before send")
        #time.sleep(10);
        #s.sendall('GET / HTTP/1.1\r\nConnection: Keep-Alive\r\nHost: www.google.lt\r\n\r\n')
        data=s.recv(52)
        print("after send");
        s.close()
        if string.find(data,"HTTP/1.1 200 OK") == -1:
            print("Lost Connection")
        print(data)
        time.sleep(2)
except KeyboardInterrupt:
    print("CTRL C occured")
except socket.error:
    print("socket error occured: ")
except socket.timeout:
    print("timeout error")

我已经评论了sendall函数来测试recv如何生成超时异常。但问题是我得到socket.error异常。如果我将最后一行代码更改为：

except socket.timeout:
    print("timeout error")
except socket.error:
     print("socket error occured: ")

然后我得到socket.timeout异常。那么真正产生了什么异常？

Answer 1

socket.timeout是socket.error的子类。真的是socket.timeout。当你首先抓住socket.error时，你会发现一个更普遍的情况。

>>> issubclass(socket.timeout, socket.error)
True

此代码是正确的：

except socket.timeout:
 print("timeout error")
except socket.error:
 print("socket error occured: ")

尝试专门捕捉socket.timeout，然后抓住其他socket.error。

Python：如何区分套接字错误和超时？

1 个答案: