Question

我对以下功能感到非常沮丧。它没有在数据库中更新我的标志。我已经尝试将1和0放在引号之间而不是。我在数据库中将字段设置为小整数。你看到我做错了吗？该条目存在，但1未更新为0.

function postValue(){
    global $customerID;
    $query="SELECT flag FROM welcomecall WHERE customerID= '$customerID'";
    echo $query;
   $result = mysql_query($query) or die('Error in the query: ' . mysql_error());
   while ($row = mysql_fetch_assoc($result)) {
    echo "The customer flag is ". $row["flag"];  
    }

    if ($row['flag']=='0'){
    $query="UPDATE welcomecall SET flag='1' WHERE customerID='$customerID'";            
   $result = mysql_query($query) or die('Error in the query: ' . mysql_error());
   }
   else if($row['flag']=='1'){
    $query="UPDATE welcomecall SET flag='0' WHERE customerID='$customerID'";            
   $result = mysql_query($query) or die('Error in the query: ' . mysql_error());
   }
}

Answer 1

当while表达式退出时，将不会留下$row：

while ($row = mysql_fetch_assoc($result)) {

所以这不是真的：

if ($row['flag']=='0'){

考虑在if循环中移动while语句。

Answer 2

看起来你正在循环中使用属于循环内部的逻辑：

function postValue(){
    global $customerID;

    $query="SELECT flag FROM welcomecall WHERE customerID= '$customerID'";
    echo $query;

    $result = mysql_query($query) or die('Error in the query: ' . mysql_error());
    while ($row = mysql_fetch_assoc($result)) {
        echo "The customer flag is ". $row["flag"];  

        // Moved
        if ($row['flag']=='0'){
            $query="UPDATE welcomecall SET flag='1' WHERE customerID='$customerID'";            
            $result = mysql_query($query) or die('Error in the query: ' . mysql_error());
        }
        else if($row['flag']=='1'){
            $query="UPDATE welcomecall SET flag='0' WHERE customerID='$customerID'";            
            $result = mysql_query($query) or die('Error in the query: ' . mysql_error());
        }
    }
}

查询错误更新字段mysql

2 个答案: