Question

如何确保我的出发日期大于以下代码中的到达日期。

SELECT ArrivalDate, DATEADD(day, RAND(checksum(NEWID()))*1.5
* LengthOfStay.LengthofStay, ArrivalDate) AS DepartureDate    
FROM Bookings, LengthOfStay
ORDER BY ArrivalDate

由于

韦恩

Answer 1

DATEADD采用整数...并且随机化返回的任何十进制值都将被截断。因此，您可能只需将0添加到ArrivalDate，从而导致两个日期相同。

您可以通过在随机化中添加至少1来解决此问题：

SELECT ArrivalDate, DATEADD(day, 1 + RAND(checksum(NEWID()))*1.5
* LengthOfStay.LengthofStay, ArrivalDate) AS DepartureDate    
FROM Bookings, LengthOfStay
ORDER BY ArrivalDate

Answer 2

尝试此查询

SELECT * FROM
    (
      SELECT 
          ArrivalDate, 
          DATEADD(day, RAND(checksum(NEWID()))*1.5   * LengthOfStay.LengthofStay, ArrivalDate) AS DepartureDate    
      FROM   
          Bookings, LengthOfStay
    ) a
WHERE a.DepartureDate > a.ArrivalDate
ORDER BY a.ArrivalDate

出发日期大于抵达日期

2 个答案: