使用Sum更新查询

时间:2013-02-20 18:59:33

标签: sql sql-server select sum

我有2个代码,我遇到了麻烦。我看了一些其他的答案但完全糊涂了。这是SQL代码..(它是Access,SQL直通查询)

UPDATE    TOP (500) InventorySuppliers
SET              BoydQuantityAvailable = SUM(Boyd0004Daily.QOH), Cost = Boyd0004Daily.Cost
FROM         Boyd0004Daily INNER JOIN
                      InventorySuppliers ON Boyd0004Daily.LocalSKU = InventorySuppliers.LocalSKU
WHERE     (InventorySuppliers.SupplierID = 4) AND (NOT (InventorySuppliers.BoydQuantityAvailable = SUM(Boyd0004Daily.QOH))) OR
                      (InventorySuppliers.SupplierID = 4) AND (NOT (InventorySuppliers.Cost = Boyd0004Daily.Cost))

它不喜欢SUM上的更新(Boyd0004Daily.QOH),但对于我的生活,我还没有弄清楚如何重写它,所以它做一个选择,然后用1个查询进行更新。

2 个答案:

答案 0 :(得分:1)

您错过了group by。每次使用聚合函数时,都必须包含一个包含所有未聚合的列的组。

您还在SUM条款中使用WHERE,但这不起作用。如果要根据汇总过滤结果,则必须使用HAVING

答案 1 :(得分:0)

你要做的第一件事是让选择出来:

select *
from InventorySuppliers i
inner join (select LocalSKU, SUM(QOH) QOH_SUM, MAX(Cost) Cost --max or min
            from Boyd0004Daily
            group by LocalSKU) a 
        on a.LocalSKU = i.LocalSKU
where i.SupplierID = 4
and ((i.BoydQuantityAvailable != a.QOH_SUM))
    OR i.Cost != a.Cost))

然后将您的选择转换为更新:

update i
set i.BoydQuantityAvailable = a.QOH_SUM,
    i.Cost = a.Cost
from InventorySuppliers i
inner join (select LocalSKU, SUM(QOH) QOH_SUM, MAX(Cost) Cost --max or min
            from Boyd0004Daily
            group by LocalSKU) a 
        on a.LocalSKU = i.LocalSKU
where i.SupplierID = 4
    and ((i.BoydQuantityAvailable != a.QOH_SUM))
        OR i.Cost != a.Cost))

我认为此查询应该适合您。我可能有错误,因为我无法测试您的数据。

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