Question

我从春天开始阅读有关Spring spring的内容，我想实现这个：我有一个Web应用程序，其中有两种用户存储在数据库中：

1）管理员

2）的客户端

这是spring-security.xml：

<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.0.3.xsd">

<http auto-config="true">
    <intercept-url pattern="/welcome*" access="ROLE_USER" />
</http>

<authentication-manager>
  <authentication-provider>
    <user-service>
    <user name="name" password="password" authorities="ROLE_USER" />
    </user-service>
  </authentication-provider>
</authentication-manager>

 </beans:beans>

所以如何联系：

<user-service> <user name="name" password="password" authorities="ROLE_USER" /> </user-service> 对数据库用户条目（管理员和客户端）？我将此部分添加到web.xml：

 <!-- Spring Security -->
<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>
       org.springframework.web.filter.DelegatingFilterProxy
    </filter-class>
</filter>

<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

Answer 1

你不能这样映射。

为此，您需要使用自定义UserDetailsService。使用userDetailsService，您可以从数据库加载用户并将其传递给spring安全框架。

public class UserDetailsServiceImpl implements UserDetailsService {
    public UserDetails loadUserByUsername(String userName)
            throws UsernameNotFoundException, DataAccessException {
        User user = getUser(userName); //Load user from database
        if (user == null) {
            throw new UsernameNotFoundException("User not found: " + userName);
        }
        return user;
    }
}

的security.xml

<authentication-manager>
    <authentication-provider user-service-ref="userDetailsService" />
</authentication-manager>

如何将spring-security身份验证规则与dataBase用户相关联

1 个答案: