将查询语法转换为扩展方法语法

时间:2013-02-22 00:29:31

标签: c# .net linq linq-to-entities extension-methods

我正在尝试使用AdventureWorks2012数据库和EF在我的演示应用程序中保持一致,但我需要一些帮助将此Linq语句转换为扩展方法。

return (from person in this.context.Persons
        from email in this.context.EmailAddresses
        where email.EmailAddress == emailAddress
        select person).FirstOrDefault();

对象是:

public class Person
{
    public int BusinessEntityId { get; set; }
    public string PersonType {get;set;}
    public bool NameStyle { get; set; }
    public string Title { get; set; }
    public string FirstName { get; set; }
    public string MiddleName { get; set; }
    public string LastName { get; set; }
    public string Suffix { get; set; }
    public int EmailPromotion { get; set; }
    public PersonPassword Password { get; set; }
    public virtual ICollection<PersonEmailAddress> EmailAddresses { get; set; }
}

public class PersonEmailAddress
{
    public int BusinessEntityId { get; set; }
    public int EmailAddressId { get; set; }
    public string EmailAddress { get; set; }
    public virtual Person Person { get; set; }
}

public class PersonPassword
{
    public int BusinessEntityId { get; set; }
    public string PasswordHash { get; set; }
    public string PasswordSalt { get; set; }
    public virtual Person Person { get; set; }
}

BusinessEntityId是PK的位置。 任何帮助是极大的赞赏。感谢...

1 个答案:

答案 0 :(得分:3)

下面我将完全回答你的问题。但是,我真的不明白为什么你想将你的查询翻译成扩展方法,所以我认为这个答案不是你想要的答案。如果是这样,你可以深入研究术语并重新解释这个问题吗?


首先:LINQ查询语法对于扩展方法来说是很好的语法糖。你的代码:

return (from person in this.context.Persons
        from email in this.context.EmailAddresses
        where email.EmailAddress == emailAddress
        select person).FirstOrDefault();

以下是转换为扩展方法的LINQ查询语法。两者是等价的,它们完全相同并给出相同的结果:

return this.context.Persons
    .SelectMany(p => this.context.EmailAddresses,
        (p, e) => new { Person = p, Email = e})
    .Where(pe => pe.Email == pe.Person)
    .Select(pe => pe.Person)
    .FirstOrDefault();

阅读起来不太好,而且更难理解。