Question

我在Oracle中有以下sql查询。

SELECT pr.uuid AS masterproductid, 
            (case 
                when xmltype(pr.attributes_de_de).extract('//attr[@name = "SellingPoint1"]/string/text()') IS NOt NULL THEN 'sellingpoint1'
                when xmltype(pr.attributes_de_de).extract('//attr[@name = "SellingPoint2"]/string/text()') IS NOt NULL THEN 'sellingpoint2'
            END
            ) as testt
  FROM product pr WHERE pr.defaultproductvariationid =(SELECT prv.uuid FROM  productvariation prv WHERE  prv.uuid = '3rep_vEBP6IAAAE83REjnPbb' AND pr.typecode='16')

在这种情况下 - 当'sellingpoint1'和'sellpoint2'都不为null但这个查询只返回sellpoint1时，我想要'sellpoint2'，我怎么能得到它？

感谢您的帮助

Answer 1

这将它分为两列：

SELECT pr.uuid AS masterproductid, 
            (case when xmltype(pr.attributes_de_de).extract('//attr[@name = "SellingPoint1"]/string/text()') IS NOt NULL
                 THEN 'sellingpoint1'
             end) as testsellingpoint1,
            (case when xmltype(pr.attributes_de_de).extract('//attr[@name = "SellingPoint2"]/string/text()') IS NOt NULL
                  THEN 'sellingpoint2'
             END
            ) as testsellingpoint2
  FROM product pr WHERE pr.defaultproductvariationid =(SELECT prv.uuid FROM  productvariation prv WHERE  prv.uuid = '3rep_vEBP6IAAAE83REjnPbb' AND pr.typecode='16')

我怎么能循环这个查询？

1 个答案: