Question

我正在尝试了解如何在其中一个返回多个记录时组合查询。

这是一个发票报告，我想在其中提取已开发票的产品序列号。我会尽可能地缩写脚本来澄清。在添加序列号之前，这是我的脚本：

   SELECT ARM.fcustno AS [Cust No]
,      ARM.fbcompany AS [Cust Name]
,      ARM.fcinvoice AS [Invoice No]
,      ARM.fdgldate AS [Post Date]
,      ARI.fitem AS [Item No]
,      ARI.fprodcl AS [Prod Class]
,      ARI.fshipkey AS [Qty Invoiced]
,      ARI.fpartno AS [Part No]
,      ARI.frev AS [Part Rev]
,      ARI.FTOTPRICE AS [Net Invoiced]
,      ARM.fsono AS [Sales No]
,      SOM.fcusrchr2
FROM dbo.armast ARM
INNER JOIN dbo.aritem ARI ON ARM.FCINVOICE = ARI.FCINVOICE
INNER JOIN slcdpm SLC ON SLC.fcustno = ARM.fcustno
LEFT OUTER JOIN slcdpm_ext SLCE ON SLC.identity_column = SLCE.fkey_id
LEFT OUTER JOIN somast SOM ON SOM.fsono = ARM.fsono

这会返回已开票的订单项，其价格等。当我拉入以下内容时：

SELECT ARM.fcustno AS [Cust No]
,      ARM.fbcompany AS [Cust Name]
,      ARM.fcinvoice AS [Invoice No]
,      ARM.fdgldate AS [Post Date]
,      ARI.fitem AS [Item No]
,      ARI.fprodcl AS [Prod Class]
,      ARI.fshipkey AS [Qty Invoiced]
,      ARI.fpartno AS [Part No]
,      ARI.frev AS [Part Rev]
,      ARI.FTOTPRICE AS [Net Invoiced]
,      ARM.fsono AS [Sales No]
,      SOM.fcusrchr2
,      LOTC.fcuseinlot 
FROM dbo.armast ARM
INNER JOIN dbo.aritem ARI ON ARM.FCINVOICE = ARI.FCINVOICE
INNER JOIN slcdpm SLC ON SLC.fcustno = ARM.fcustno
LEFT OUTER JOIN slcdpm_ext SLCE ON SLC.identity_column = SLCE.fkey_id
LEFT OUTER JOIN somast SOM ON SOM.fsono = ARM.fsono

--** New stuff below: ******
LEFT OUTER JOIN ShItem SHI ON SHI.fShipNo + SHI.fItemNo = ARI.fShipKey
LEFT OUTER JOIN ShSrce ON ShSrce.fcShipNo = SHI.fShipNo
                      AND ShSrce.fcItemNo = SHI.fItemNo
LEFT OUTER JOIN QaLotC LOTC ON LOTC.fcUseInDoc = ShSrce.fcShipNo + ShSrce.fcItemNo + ShSrce.fcSrcItmNo

问题是每张发票可能有多个SHSRCE记录。处理这个问题的最佳方法是什么？也许使用子查询来连接LOTC.fcuseinlot字段，以便为每条记录返回一个相应的值。

为了澄清，附加查询会为每个订单项发票返回多于1条记录，因为可以在一个订单项上为多个序列号部件开具发票。理想情况下，我希望它们像（NCC1701，R2D2，C3PO）那样连接。这就是为什么我考虑使用子查询来连接它们。

Answer 1

仍在等待OP澄清问题，但是如果多个SHSRCE记录仍然只涉及一个序列号（我假设是在LOTC.fcuseinlot中）

SELECT
    ARM.fcustno AS [Cust No] ,
    ARM.fbcompany AS [Cust Name] ,
    ARM.fcinvoice AS [Invoice No] ,
    ARM.fdgldate AS [Post Date] ,
    ARI.fitem AS [Item No] ,
    ARI.fprodcl AS [Prod Class] ,
    ARI.fshipkey AS [Qty Invoiced] ,
    ARI.fpartno AS [Part No] ,
    ARI.frev AS [Part Rev] ,
    ARI.FTOTPRICE AS [Net Invoiced] ,
    ARM.fsono AS [Sales No] ,
    SOM.fcusrchr2,
       MAX(LOTC.fcuseinlot)
FROM
    dbo.ARMAST ARM 
JOIN dbo.aritem ARI ON  ARI.FCINVOICE = ARM.FCINVOICE 
JOIN slcdpm SLC ON  SLC.fcustno = ARM.fcustno
LEFT JOIN slcdpm_ext SLCE ON  SLCE.fkey_id = SLC.identity_column
LEFT JOIN somast SOM ON  SOM.fsono = ARM.fsono
LEFT JOIN ShItem SHI ON  SHI.fShipNo + SHI.fItemNo = ARI.fShipKey
LEFT JOIN ShSrce ON  ShSrce.fcShipNo = SHI.fShipNo AND ShSrce.fcItemNo = SHI.fItemNo
LEFT JOIN QaLotC LOTC ON  LOTC.fcUseInDoc = ShSrce.fcShipNo + ShSrce.fcItemNo + ShSrce.fcSrcItmNo
GROUP BY
    ARM.fcustno ,
    ARM.fbcompany ,
    ARM.fcinvoice ,
    ARM.fdgldate ,
    ARI.fitem ,
    ARI.fprodcl ,
    ARI.fshipkey ,
    ARI.fpartno ,
    ARI.frev ,
    ARI.FTOTPRICE ,
    ARM.fsono ,
    SOM.fcusrchr2

你可以发布一些样本数据吗？

如果我找对你，请看看这种sql

create table tableA (id int, ref varchar(50))

insert into tableA
select 1, 3536757616
union select 1, 3536757617
union select 1, 3536757618
union select 2, 3536757628
union select 2, 3536757629
union select 2, 3536757630

我知道我可以使用

简单地连接引用

SELECT distinct
    id,
    stuff ( ( SELECT
                  '/ ' + ref 
              FROM
                  tableA tableA_1
              where tableA_1.id = tableA_2.id
    FOR XML PATH ( '' ) ) , 1 , 2 , '' )
from TableA tableA_2

给予

1   3536757616/ 3536757617/ 3536757618
2   3536757628/ 3536757629/ 3536757630

Answer 2

结合查询？和做UNION一样？

Answer 3

我们真正需要知道的是，您将使用哪些基础来选择哪些可能的记录具有您想要返回的值？这将决定最适合你的可能性。

由于您没有添加任何列并且您正在使用左连接（因此不会从连接中排除任何记录）除了延长处理时间之外，您希望通过添加这些连接来实现什么？

Answer 4

您的问题上有一个SQL Server 2000标记，所以我不确定这对您是否可行。在SQL Server 2005及更高版本中，您可以创建自定义聚合函数。我使用了一个聚合函数FormDelimitedString，它正是你正在寻找的。

有一个页面here描述了如何实现这个功能 - 它被编写为.NET程序集，然后在查询中执行。有了这个，您的查询就变成......

SELECT ARM.fcustno AS [Cust No]
,      ARM.fbcompany AS [Cust Name]
-- (a few fields skipped for brevity)
,      SOM.fcusrchr2
-- Aggregate function will combine multiple values into a single string - 'value1, value2, value3' etc
,   dbo.FormDelimitedString(LOTC.fcuseinlot) AS ConcatenatedValues
FROM dbo.armast ARM
INNER JOIN dbo.aritem ARI ON ARM.FCINVOICE = ARI.FCINVOICE
INNER JOIN slcdpm SLC ON SLC.fcustno = ARM.fcustno
LEFT OUTER JOIN slcdpm_ext SLCE ON SLC.identity_column = SLCE.fkey_id
LEFT OUTER JOIN somast SOM ON SOM.fsono = ARM.fsono
LEFT OUTER JOIN ShItem SHI ON SHI.fShipNo + SHI.fItemNo = ARI.fShipKey
LEFT OUTER JOIN ShSrce ON ShSrce.fcShipNo = SHI.fShipNo
                      AND ShSrce.fcItemNo = SHI.fItemNo
LEFT OUTER JOIN QaLotC LOTC ON LOTC.fcUseInDoc = ShSrce.fcShipNo + ShSrce.fcItemNo + ShSrce.fcSrcItmNo

-- Group by clause needed as its an aggregate function
GROUP BY ARM.fcustno, ARM.fbcompany, SOM.fcusrchr2

合并查询

4 个答案: