Question

所以，我在这里有这个问题：

$strSQL = "SELECT formas.*, SMS_SERVISI.IDTICKET, SMS_SERVISI.MBYLLUR,SMS_SERVISI.time_added,servis_furnitor.id_servis,servis_furnitor.furnitori,servis_furnitor.kohezgjatja
FROM formas  
LEFT JOIN servis_furnitor ON formas.furnitori = servis_furnitor.id_servis 
LEFT JOIN SMS_SERVISI ON formas.ID = SMS_SERVISI.IDTICKET 
ORDER BY formas.id DESC 
WHERE $today-formas.data_fillim > servis_furnitor.kohezgjatja";

最后一行是错的，我知道，我的意思是我可以去那里.. 我有这个订单，他们的开始日期是formas.data_fillim，我有今天的日期：

$today = date("Ymd");

因此，$today-formas.data_fillim之间的差异不应大于servis_furnitor.kohezgjatja这是一个整数本身，它会显示天数

formas.data_fillim

是日期类型..

我需要提取所有数据，这些数据与今天的日期和开始日期的差异不大于“kohezgjatja”中预定义的天数

任何帮助请... 感谢

更新

$today = date("Y-m-d H:i:s", time());  


echo $strSQL = "SELECT  formas.*,
        SMS_SERVISI.IDTICKET,
        SMS_SERVISI.MBYLLUR,
        SMS_SERVISI.time_added,
        servis_furnitor.id_servis,
        servis_furnitor.furnitori,
        servis_furnitor.kohezgjatja
FROM formas
LEFT JOIN servis_furnitor
        ON formas.furnitori = servis_furnitor.id_servis
LEFT JOIN SMS_SERVISI
        ON formas.ID = SMS_SERVISI.IDTICKET
WHERE DATEDIFF ( day , '$today' , formas.data_fillim ) > servis_furnitor.kohezgjatja
ORDER BY formas.id DESC"

Answer 1

SELECT语句的正确格式为

SELECT ....
FROM...
WHERE ...
GROUP ....
ORDER BY...

所以在你的情况下，

SELECT  formas.*,
        SMS_SERVISI.IDTICKET,
        SMS_SERVISI.MBYLLUR,
        SMS_SERVISI.time_added,
        servis_furnitor.id_servis,
        servis_furnitor.furnitori,
        servis_furnitor.kohezgjatja
FROM formas
LEFT JOIN servis_furnitor
        ON formas.furnitori = servis_furnitor.id_servis
LEFT JOIN SMS_SERVISI
        ON formas.ID = SMS_SERVISI.IDTICKET
WHERE DATEDIFF ( day , $TODAY , formas.data_fillim )  > servis_furnitor.kohezgjatja
ORDER BY formas.id DESC

Answer 2

这样的事情应该有效：

where formas.data_fillim <= DateAdd(day, servis_furnitor.kohezgjatja, getdate())

您可能需要在servis_furnitor.kohezgjatja前面加一个减号，具体取决于您在那里存放的东西。

SQL查询条件与日期

2 个答案: