Question

我刚注意到FULL OUTER JOIN无效 Oracle 。

其他查询工作正常，但是当我使用全外连接触发查询时，需要时间并且断开连接会抛出错误。

ORA-03113：通讯渠道上的文件结尾

RIGHT OUTER JOIN 和 LEFT OUTER JOIN 正常工作。

对于下面的查询，我可以使用完全外部联接来获取所有记录？

select * from 
(
    select 
    FTM_OFFICE_ID,
    NVL(SUM(FTD_NRS_AMOUNT),0) as TOTAL 
    from FMS_TRANS_DTL 
    inner join FMS_TRANS_MST ON FMS_TRANS_MST.FTM_TRANS_MST_ID = FMS_TRANS_DTL.FTD_TRANS_MST_ID 
    inner join FMS_FC_VOUCHER_CONFIG ON FMS_FC_VOUCHER_CONFIG.FFVC_VOUCHER_ID = FMS_TRANS_MST.FTM_VOUCHER_ID 
    where FFVC_ACCOUNT_TYPE = 3 and FTM_FISCAL_YEAR='2066/67'
    and FTD_ACC_ID in (select distinct FDP_DHARAUTI_C_ACC_ID from FMS_DHARAUTI_PARAMETER where FDP_FISCAL_YEAR='2066/67' )
    /*and FTD_ACC_ID in (591)*/
    group by FTM_OFFICE_ID 
) T1
full outer join
(
    select 
    FTM_OFFICE_ID,
    NVL(SUM(FTD_NRS_AMOUNT),0) as TOTAL 
    from FMS_TRANS_DTL 
    inner join FMS_TRANS_MST ON FMS_TRANS_MST.FTM_TRANS_MST_ID = FMS_TRANS_DTL.FTD_TRANS_MST_ID 
    inner join FMS_FC_VOUCHER_CONFIG ON FMS_FC_VOUCHER_CONFIG.FFVC_VOUCHER_ID = FMS_TRANS_MST.FTM_VOUCHER_ID 
    where FFVC_ACCOUNT_TYPE = 3 and FTM_FISCAL_YEAR='2066/67'
    /*and FTD_ACC_ID in (592)*/
    and FTD_ACC_ID in 
    (select distinct FDP_DHARAUTI_L_ACC_ID from FMS_DHARAUTI_PARAMETER where FDP_FISCAL_YEAR='2066/67' )
    group by FTM_OFFICE_ID 
) T2
on T1.FTM_OFFICE_ID=T2.FTM_OFFICE_ID
/*
 The no. of rows that T1 can have can be different that no. of rows T2 can have. 
 Its not necessary any OFFICE_ID must have amount under any FTD_ACC_ID.
*/

注意到如果我在FTD_ACC_ID的条件下删除子查询，则查询运行完美。为什么？

Answer 1

在Oracle中支持

FULL OUTER JOIN。

您遇到的错误听起来像是Oracle错误，或者可能是某种形式的损坏。每当发生ORA-03113时，您应该在alert.log中找到错误。

通常，如果您收到此错误，那是因为该会话的后台oracle系统进程已经死亡（这几乎总是由于Oracle内部错误）。

这对友好的本地DBA来说是一个问题。

Answer 2

基于您的查询+后续评论的解决方法是：

alter session set "_optimizer_cost_based_transformation"=off;

例如：

SQL> alter session set "_optimizer_cost_based_transformation"=off;

Session altered.

或在sql中作为提示

/*+ opt_param('_optimizer_cost_based_transformation', 'off')

例如

select /*+ opt_param('_optimizer_cost_based_transformation', 'off') */ * from 
(
    select FTM_OFFICE_ID,

你可能会遇到错误：

BUG 4204383: ORA-7445[KKQTNLOCBK] USING QUERY WITH SUBQUERY AND FULL OUTER JOIN

已修补仅在10.2.0.2之后可用（在10.2.0.4中完全修复）。

Answer 3

如果确实（无论出于何种原因）完全外部联接不适合您，请使用

-- all rows present in both t1 and t2
select * from t1 inner join t2
union all
-- all rows present in t1 but not in t2
select * from t1 left outer join t2 where t2.pk is null
union all
-- all rows present in t2 but not in t1
select * from t1 right outer join t2 where t1.pk is null

而不是

select * from t1 full outer join t2

这将返回相同的结果。

Answer 4

您可以尝试此查询：

 SELECT 
    FTM_OFFICE_ID,
    NVL(SUM(FTD_NRS_AMOUNT),0) AS TOTAL 
    FROM FMS_TRANS_DTL 
    INNER JOIN FMS_TRANS_MST ON FMS_TRANS_MST.FTM_TRANS_MST_ID = FMS_TRANS_DTL.FTD_TRANS_MST_ID 
    INNER JOIN FMS_FC_VOUCHER_CONFIG ON FMS_FC_VOUCHER_CONFIG.FFVC_VOUCHER_ID = FMS_TRANS_MST.FTM_VOUCHER_ID 
    WHERE FFVC_ACCOUNT_TYPE = 3 AND FTM_FISCAL_YEAR='2066/67'
    AND FTD_ACC_ID IN (
            SELECT DISTINCT FDP_DHARAUTI_C_ACC_ID FROM FMS_DHARAUTI_PARAMETER WHERE FDP_FISCAL_YEAR='2066/67'
            UNION
            SELECT DISTINCT FDP_DHARAUTI_L_ACC_ID FROM FMS_DHARAUTI_PARAMETER WHERE FDP_FISCAL_YEAR='2066/67'   
            )
    GROUP BY FTM_OFFICE_ID

Answer 5

看起来唯一不同的是FTD_ACC_ID值为105和110的单独总计。一种方法是使用CASE语句分别对它们进行总计。

select 
FTM_OFFICE_ID,
NVL(SUM(CASE FTD_ACC_ID WHEN 105 THEN FTD_NRS_AMOUNT ELSE 0 END),0) as TOTAL_105,
NVL(SUM(CASE FTD_ACC_ID WHEN 110 THEN FTD_NRS_AMOUNT ELSE 0 END),0) as TOTAL_110,
 from FMS_TRANS_DTL 
inner join FMS_TRANS_MST ON FMS_TRANS_MST.FTM_TRANS_MST_ID = FMS_TRANS_DTL.FTD_TRANS_MST_ID 
inner join FMS_FC_VOUCHER_CONFIG ON FMS_FC_VOUCHER_CONFIG.FFVC_VOUCHER_ID = FMS_TRANS_MST.FTM_VOUCHER_ID 
where FFVC_ACCOUNT_TYPE = 3 and FTM_FISCAL_YEAR='2066/67'
and FTD_ACC_ID in (105,110)
group by FTM_OFFICE_ID

Answer 6

在您的查询中使用UNION代替FULL OUTER JOIN，如此

select * from 
(

select 
FTM_OFFICE_ID,
NVL(SUM(FTD_NRS_AMOUNT),0) as TOTAL 
from FMS_TRANS_DTL 
inner join FMS_TRANS_MST ON FMS_TRANS_MST.FTM_TRANS_MST_ID = FMS_TRANS_DTL.FTD_TRANS_MST_ID 
inner join FMS_FC_VOUCHER_CONFIG ON FMS_FC_VOUCHER_CONFIG.FFVC_VOUCHER_ID = FMS_TRANS_MST.FTM_VOUCHER_ID 
where FFVC_ACCOUNT_TYPE = 3 and FTM_FISCAL_YEAR='2066/67'
and FTD_ACC_ID = 105
group by FTM_OFFICE_ID ) T1 union (select FTM_OFFICE_ID,
NVL(SUM(FTD_NRS_AMOUNT),0) as TOTAL 
from FMS_TRANS_DTL 
inner join FMS_TRANS_MST ON FMS_TRANS_MST.FTM_TRANS_MST_ID = FMS_TRANS_DTL.FTD_TRANS_MST_ID 
inner join FMS_FC_VOUCHER_CONFIG ON FMS_FC_VOUCHER_CONFIG.FFVC_VOUCHER_ID = FMS_TRANS_MST.FTM_VOUCHER_ID 
where FFVC_ACCOUNT_TYPE = 3 and FTM_FISCAL_YEAR='2066/67'
and FTD_ACC_ID = 110
group by FTM_OFFICE_ID )T2

在oracle中完全加入

6 个答案: