总结记录

Question

我有一个记录表，如

╔═════╦══════╦══════════╦══════════╗
║ PID ║ NAME ║  DATE1   ║  DATE2   ║
╠═════╬══════╬══════════╬══════════╣
║ 123 ║ john ║ 20110401 ║ 19700101 ║
║ 123 ║ john ║ 20110401 ║ 19700101 ║
║ 123 ║ john ║ 20110401 ║ 19700101 ║
║ 323 ║ mike ║ 20110401 ║ 19900101 ║
║ 323 ║ mike ║ 20110401 ║ 19900101 ║
╚═════╩══════╩══════════╩══════════╝

{p> query1 count上的pid

query2如果所有四个字段都相同，则记录将被视为一条记录，否则单个记录和记录将计入pid订单。

以上结果是：

╔═════╦══════════════╦═════════════╗
║ PID ║ TOTALRECORDS ║ TOTALUNIQUE ║
╠═════╬══════════════╬═════════════╣
║ 123 ║            3 ║           1 ║
║ 323 ║            2 ║           1 ║
╚═════╩══════════════╩═════════════╝

我做了select pid,count(pid),(select count(pid) group by pid,name,date1,date2) from <table> group by pid;

但是我收到了错误......请更正我的代码。

Answer 1

SELECT  pid,
        COUNT(*) totalRecords,
        COUNT(DISTINCT name, date1, date2) totalUnique
FROM    TableName
GROUP   BY pid

• SQLFiddle Demo
• SQLFiddle Demo (with not unique record)

结果

╔═════╦══════════════╦═════════════╗
║ PID ║ TOTALRECORDS ║ TOTALUNIQUE ║
╠═════╬══════════════╬═════════════╣
║ 123 ║            3 ║           1 ║
║ 323 ║            2 ║           1 ║
╚═════╩══════════════╩═════════════╝