Question

我试图放弃一张桌子，然后才遇到这个问题QUESTION

并且成功地解决了但是现在我试图放弃桌子并且我得到了这个错误：

ERROR: Error 1005: Can't create table 'radiotaxi_final.#sql-108_28' (errno: 150)

声明：

ALTER TABLE `RadioTaxi_Final`.`DireccionConductor` CHANGE COLUMN `Conductor_cedula` `Conductor_cedula` INT(11) NOT NULL  , 

  ADD CONSTRAINT `fk_DireccionConductor_Conductor1`

  FOREIGN KEY (`Conductor_cedula` )

  REFERENCES `RadioTaxi_Final`.`Conductor` (`cedula` )

  ON DELETE NO ACTION

  ON UPDATE NO ACTION

结果：

SQL script execution finished: statements: 11 succeeded, 1 failed

表：

CREATE TABLE `conductor` (  `cedula` int(10) unsigned NOT NULL,  `apellidos` varchar(30) COLLATE utf8_spanish2_ci NOT NULL,  `nombres` varchar(30) COLLATE utf8_spanish2_ci NOT NULL,  `fechaNacimiento` date NOT NULL,  PRIMARY KEY (`cedula`)) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_spanish2_ci

Answer 1

创建FOREIGN KEY时，引用列和引用列的数据类型必须完全相同。在您引用的表格中，conductor.cedula的类型为INT(10) UNSIGNED。您试图在DireccionConductor.Conductor_cedula上INT(11)创建FK，隐式SIGNED。修改你的语句如下，使类型匹配：

ALTER TABLE `RadioTaxi_Final`.`DireccionConductor`
  /* INT(10) UNSIGNED type matches the referenced table */
  CHANGE COLUMN `Conductor_cedula` `Conductor_cedula` INT(10) UNSIGNED NOT NULL  , 
  ADD CONSTRAINT `fk_DireccionConductor_Conductor1`
    FOREIGN KEY (`Conductor_cedula` )
    REFERENCES `RadioTaxi_Final`.`Conductor` (`cedula` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION

错误1005：无法创建表

1 个答案: