Question

<form method="post">
  <select name="select_employee" id="select_employee">
    <?php $allemp=$this->AllEmployees; ?>
    <option selected value="">Select an employee..</option>
    <?php foreach($allemp as $row){ echo "<option value=".$row[ 'Id']. ">".$row[ 'Etunimi']. " - ". $row[ 'Sukunimi']. "</option>"; } ?>
  </select>
  <input type="hidden" name="send" value="namesent">
  <input type="submit" value="submit" id="button">
</form>
<br/>
<br/>

当我提交此表单时，我会停留在同一页面上，但我希望同时保持之前选择的选项可见..我怎么能这样做？我试过了：

document.getElementById('select_employee').value = "<?php echo $_GET['select_employee'];?>";

但它不起作用..

Answer 1

这里：

 foreach($allemp as $row){
     echo "<option " . (isset($_POST['select_employee']) && $_POST['select_employee'] == $row['Id'] ? ' selected ' : '') . " value=".$row['Id'].">".$row['Etunimi']." - ".$row['Sukunimi']."</option>";
}

Answer 2

试试这个：

 $selected = ($row['Id'] == $_REQUEST['select_employee'])?'selected="selected"':'';
 echo '<option '.$selected.' value="'.$row['Id'].'">'.$row['Etunimi'].' - '. $row['Sukunimi'].'</option>';

在echo options ($selected = ($row['Id'] == $_REQUEST['select_employee'])?'selected="selected"':'';)
在旁边选项中添加了'.$selected.'。

您的代码变为：复制粘贴代码而不是您的代码

<form method="post">
  <select name="select_employee" id="select_employee">
    <?php $allemp=$this->AllEmployees; ?>
    <option selected value="">Select an employee..</option>
    <?php foreach($allemp as $row){ 
      $selected = ($row['Id'] == $_REQUEST['select_employee'])?'selected="selected"':'';
     echo '<option '.$selected.' value="'.$row['Id'].'">'.$row['Etunimi'].' - '. $row['Sukunimi'].'</option>';
 } ?>
  </select>
  <input type="hidden" name="send" value="namesent">
  <input type="submit" value="submit" id="button">
</form>
<br/>
<br/>

从下拉框中保存所选选项

2 个答案: