如何合并两个结果

Question

我有两种类型的sql查询它返回相同的数据，我需要合并其中两个，如果我使用Union 它把第二个结果放到第一个结果但我不需要这个，我需要合并日期或有没有办法将两个SQL查询合并到一个查询？

SELECT TO_CHAR(s.CR_DATE, 'DD') DAY, TO_CHAR(s.CR_DATE, 'MM') MONTH, count(*) total FROM SUSR s
left outer join SUSR_ACCT sa on (s.SUSR_ID = sa.SUSR_ID) 
WHERE s.CR_DATE > '01-01-2012' AND s.CR_DATE < '01-01-2014' and sa.ACCT_ID =  123
GROUP BY TO_CHAR(s.CR_DATE, 'DD'), TO_CHAR(s.CR_DATE, 'MM') 



SELECT TO_CHAR(s.CR_DATE, 'DD') DAY, TO_CHAR(s.CR_DATE, 'MM') MONTH, count(*) total FROM SUSR s
WHERE s.CR_DATE > '01-01-2012' AND s.CR_DATE < '01-01-2014' and s.APP_ACCT_ID =  123
GROUP BY TO_CHAR(s.CR_DATE, 'DD'), TO_CHAR(s.CR_DATE, 'MM')
ORDER BY month, day

谢谢！

Answer 1

您想要汇总两个结果：

SELECT day, month, SUM(total)
  FROM ( /* first_query */
        UNION ALL
         /* second_query */)
 GROUP BY day, month

Answer 2

假设我正确理解合并策略背后的意图，您应该添加第二级GROUP BY，并总计相应的总数，如下所示：

SELECT DAY, MONTH, SUM(total) FROM (
    SELECT TO_CHAR(s.CR_DATE, 'DD') DAY, TO_CHAR(s.CR_DATE, 'MM') MONTH, count(*) total
    FROM SUSR s
    left outer join SUSR_ACCT sa on (s.SUSR_ID = sa.SUSR_ID) 
    WHERE s.CR_DATE > '01-01-2012' AND s.CR_DATE < '01-01-2014' and sa.ACCT_ID =  123
    GROUP BY TO_CHAR(s.CR_DATE, 'DD'), TO_CHAR(s.CR_DATE, 'MM') 
UNION ALL
    SELECT TO_CHAR(s.CR_DATE, 'DD') DAY, TO_CHAR(s.CR_DATE, 'MM') MONTH, count(*) total
    FROM SUSR s
    WHERE s.CR_DATE > '01-01-2012' AND s.CR_DATE < '01-01-2014' and s.APP_ACCT_ID =  123
    GROUP BY TO_CHAR(s.CR_DATE, 'DD'), TO_CHAR(s.CR_DATE, 'MM') 
) src
GROUP BY DAY, MONTH
ORDER BY DAY, MONTH

如果第一个结果中有1 2 5行，第二个结果中有1 2 4行，您将在输出中看到1 2 9行（即前两列将是用于分组，最后一个将总计）。