当我使用多个选择下拉列表从国家/地区表中选择国家/地区时，如何从州表中获取国家/地区州列表？这是我的编码。
CREATE TABLE `countries` (
`countryID` varchar(3) NOT NULL default '',
`countryName` varchar(52) NOT NULL default '',
`localName` varchar(45) NOT NULL,
`webCode` varchar(2) NOT NULL,
`region` varchar(26) NOT NULL,
`continent` enum('Asia','Europe','North America','Africa','Oceania','Antarctica','South America') NOT NULL,
`latitude` double NOT NULL default '0',
`longitude` double NOT NULL default '0',
`surfaceArea` float(10,2) NOT NULL default '0.00',
`population` int(11) NOT NULL default '0',
PRIMARY KEY (`countryID`),
UNIQUE KEY `webCode` (`webCode`),
UNIQUE KEY `countryName` (`countryName`),
KEY `region` (`region`),
KEY `continent` (`continent`),
KEY `surfaceArea` (`surfaceArea`),
KEY `population` (`population`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
states表的结构：CREATE TABLE `states` (
`stateID` smallint(5) unsigned NOT NULL auto_increment,
`stateName` varchar(50) NOT NULL default '',
`countryID` varchar(3) NOT NULL,
`latitude` double NOT NULL default '0',
`longitude` double NOT NULL default '0',
PRIMARY KEY (`stateID`),
KEY `stateName` (`stateName`),
KEY `countryID` (`countryID`),
KEY `unq` (`countryID`,`stateName`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
countries表的数据（LIMIT 0,500）INSERT INTO `countries` (`countryID`, `countryName`, `localName`, `webCode`, `region`, `continent`, `latitude`, `longitude`, `surfaceArea`, `population`) VALUES
('BRA','Brazil','Brasil','BR','South America','South America',-10,-55,8547403.00,170115000),
('CHN','China','Zhongquo','CN','Eastern Asia','Asia',35,105,9572900.00,1277558000),
('FRA','France','France','FR','Western Europe','Europe',47,2,551500.00,59225700),
('IND','India','Bharat/India','IN','Southern and Central Asia','Asia',28.47,77.03,3287263.00,1013662000),
('USA','USA','United States','US','North America','North America',38,-97,9363520.00,278357000);
COMMIT;
states表的数据（LIMIT 0,500）INSERT INTO `states` (`stateID`, `stateName`, `countryID`, `latitude`, `longitude`) VALUES
(5,'California','USA',37.42,-122.06),
(6,'Beijing','CHN',39.93,116.39),
(9,'Iowa','USA',43.03,-96.09),
(10,'New York','USA',40.76,-73.97),
(12,'... ....','CHN',32.06,118.78);
COMMIT;
<? $Type_sql="SELECT countryName FROM countries ORDER by countryName ASC";
$Type_result=mysql_query($Type_sql);
while($Type_rows=mysql_fetch_array($Type_result)){
echo "<option value='";
echo $Type_rows['countryName'];
echo "'>";
echo $Type_rows['countryName'];
echo "</option>";
} ?>
</select>
<? $Type_sql="SELECT stateName FROM countries c, states s where c.countryID = s.countryID ORDER by stateName ASC";
$Type_result=mysql_query($Type_sql);
while($Type_rows=mysql_fetch_array($Type_result)){
echo "<option value='";
echo $Type_rows['stateName'];
echo "'>";
echo $Type_rows['stateName'];
echo "</option>";
} ?>
</select>
答案 0 :(得分：0)
这可以通过将状态下拉列表的代码放入一个单独的php处理程序来完成，稍微修改一下：
<select name="state">
<?php
$countryID= mysql_real_escape_string($_GET['countryID']);
$Type_sql="SELECT stateName FROM states s where s.countryID = '$countryID' ORDER by stateName ASC";
$Type_result=mysql_query($Type_sql);
while($Type_rows=mysql_fetch_array($Type_result)){
echo "<option value='";
echo $Type_rows['stateName'];
echo "'>";
echo $Type_rows['stateName'];
echo "</option>";
}
?>
</select>
每次国家/地区选择列表中都有onChange事件时，javascript将使用Ajax调用此脚本。请参考像http://www.javascriptkit.com/dhtmltutors/ajaxgetpost.shtml这样的ajax文档，或者使用jQuery：http://api.jquery.com/jQuery.get/
现在也可以像你的计划那样修改状态选择的内容，但是你需要两个选择列表，一个隐藏列表来存储你删除的条目或者只是所有这些。
答案 1 :(得分：0)
这是一个完全有效的代码。 只需将此代码放在php页面中，然后将onChange参数中的表单名称更改为页面名称。另外，在 mysql_select_db 中更改数据库名称。
我的网页名称是 form1.php
<html>
<body>
<form name="form1">
<?php
if(isset($_REQUEST['stateId']))
{
$stateId = $_REQUEST['stateId'];
}
else
{
$stateId = "";
}
$conn = mysql_connect("localhost","root","");
$dbSelect = mysql_select_db("test");
$Type_sql="SELECT countryID,countryName FROM countries ORDER by countryName ASC";
$Type_result=mysql_query($Type_sql);
echo"Countries:<select onChange=\"window.location='form1.php?stateId='+this.value\">";
while($Type_rows=mysql_fetch_array($Type_result)){
if($Type_rows['countryID']==$_REQUEST['stateId'])
{
echo "<option value='".$Type_rows['countryID']."' selected>";
echo $Type_rows['countryName'];
echo "</option>";
}
else
{
echo "<option value='".$Type_rows['countryID']."'>";
echo $Type_rows['countryName'];
echo "</option>";
}
}
echo"</select>";
$Type_sql="SELECT stateName FROM states where countryID = '$stateId' ORDER by stateName ASC";
$Type_result=mysql_query($Type_sql);
echo"States:<select><option value=''>--select--</option>";
while($Type_rows=mysql_fetch_array($Type_result)){
echo "<option value='";
echo $Type_rows['stateName'];
echo "'>";
echo $Type_rows['stateName'];
echo "</option>";
}
echo"</select>";
?>
</form>
</body>
</html>
答案 2 :(得分：0)
嗨艾哈迈德，
请看下面的代码。 我重新编写了代码并修改了多个选项 无论如何，我忽略了javascript验证。请继续处理，此页面的名称为 form3.php
<html>
<head>
<script type="text/javascript">
function viewstates()
{
jQuery('#langucountry').change(function () { });
}
$(function() {
$('#basicmultiselect').multiSelect({select_all_min: 3});
$('#langucountry').multiSelect({
select_all_min: 3, no_selection: "Please select!", selected_text: " clicked" });
$('#methods').multiSelect(); });
</script>
</head>
<body>
<form name="form3" action="form3.php" method="post">
<?php
/****** connection string *******/
/* start */
$conn = mysql_connect("localhost","root","");
$dbSelect = mysql_select_db("test");
/* end */
/*----checks whether form is submited -------*/
if(isset($_POST['cbocountry']))
{
$lstStates = array();
foreach($_POST['cbocountry'] as $countryCode)
{
$fetch_states="SELECT stateName FROM states where countryID = '$countryCode' ORDER by stateName ASC";
$Type_result=mysql_query($fetch_states);
while($Type_rows=mysql_fetch_array($Type_result)){
if(!in_array($Type_rows['stateName'],$lstStates))
array_push($lstStates,$Type_rows['stateName']);
}
}
}
$Type_sql="SELECT countryID,countryName FROM countries ORDER by countryName ASC";
$Type_result=mysql_query($Type_sql);
echo"Countries:<select id=\"langucountry\" name=\"cbocountry[]\" class=\"arc90_multiselect\" multiple=\"multiple\" title=\"Languages\"\>";
while($Type_rows=mysql_fetch_array($Type_result)){
echo "<option value='".$Type_rows['countryID']."'>";
echo $Type_rows['countryName'];
echo "</option>";
}
echo"</select>";
echo"States:<select><option value=''>--select--</option>";
if(count($lstStates) > 0)
{
foreach($lstStates as $item)
{
echo "<option value='";
echo $item;
echo "'>";
echo $item;
echo "</option>";
}
}
echo"</select>";
echo"<input type=\"submit\" value=\"submit\" text=\"submit\"/>";
?>
</form>
</body>
</html>
<强>享受!!!!