处理异常的Python线程池

时间:2013-03-12 10:56:47

标签: python multithreading exception-handling threadpool

我一直在寻找一个简单的python线程池模式的良好实现,实际上找不到任何适合我需要的东西。我正在使用python 2.7,我发现的所有模块都不起作用,或者没有正确处理工作程序中的异常。我想知道是否有人知道可以提供我正在搜索的功能类型的库。非常感谢。

多处理

我的第一次尝试是使用内置的multiprocessing模块,但由于这不使用线程而是使用子进程,而是遇到了无法对对象进行pickle的问题。不要去这里。

from multiprocessing import Pool

class Sample(object):
    def compute_fib(self, n):
        phi = (1 + 5**0.5) / 2
        self.fib = int(round((phi**n - (1-phi)**n) / 5**0.5))

samples = [Sample() for i in range(8)]
pool = Pool(processes=8)
for s in samples: pool.apply_async(s.compute_fib, [20])
pool.join()
for s in samples: print s.fib

# PicklingError: Can't pickle <type 'instancemethod'>: attribute lookup __builtin__.instancemethod failed

期货

所以我看到有一个python 3.2 here的一些很酷的并发功能的后端口。这似乎完美且易于使用。问题是当你在其中一个worker中得到一个异常时,你只得到异常的类型,例如“ZeroDivisionError”但没有回溯,因此没有指示哪一行导致了异常。代码变得无法调试。不行。

from concurrent import futures

class Sample(object):
    def compute_fib(self, n):
        phi = (1 + 5**0.5) / 2
        1/0
        self.fib = int(round((phi**n - (1-phi)**n) / 5**0.5))

samples = [Sample() for i in range(8)]
pool = futures.ThreadPoolExecutor(max_workers=8)
threads = [pool.submit(s.compute_fib, 20) for s in samples]
futures.wait(threads, return_when=futures.FIRST_EXCEPTION)
for t in threads: t.result()
for s in samples: print s.fib


#    futures-2.1.3-py2.7.egg/concurrent/futures/_base.pyc in __get_result(self)
#    354     def __get_result(self):
#    355         if self._exception:
#--> 356             raise self._exception
#    357         else:
#    358             return self._result
#
# ZeroDivisionError: integer division or modulo by zero

工作者池

我找到了这种模式的其他实现here。这次发生异常时会打印出来,但是我的ipython交互式解释器处于挂起状态,需要从其他shell中杀死。不行。

import workerpool

class Sample(object):
    def compute_fib(self, n):
        phi = (1 + 5**0.5) / 2
        1/0
        self.fib = int(round((phi**n - (1-phi)**n) / 5**0.5))

samples = [Sample() for i in range(8)]
pool = workerpool.WorkerPool(size=8)
for s in samples: pool.map(s.compute_fib, [20])
pool.wait()
for s in samples: print s.fib

# ZeroDivisionError: integer division or modulo by zero
# ^C^C^C^C^C^C^C^C^D^D
# $ kill 1783

线程池

还有另一种实施here。这次发生异常时,会将其打印到stderr,但脚本不会被中断而是继续执行,这会违反异常的目的并使事情变得不安全。仍然无法使用。

import threadpool

class Sample(object):
    def compute_fib(self, n):
        phi = (1 + 5**0.5) / 2
        1/0
        self.fib = int(round((phi**n - (1-phi)**n) / 5**0.5))

samples = [Sample() for i in range(8)]
pool = threadpool.ThreadPool(8)
requests = [threadpool.makeRequests(s.compute_fib, [20]) for s in samples]
requests = [y for x in requests for y in x]
for r in requests: pool.putRequest(r)
pool.wait()
for s in samples: print s.fib

# ZeroDivisionError: integer division or modulo by zero
# ZeroDivisionError: integer division or modulo by zero
# ZeroDivisionError: integer division or modulo by zero
# ZeroDivisionError: integer division or modulo by zero
# ZeroDivisionError: integer division or modulo by zero
# ZeroDivisionError: integer division or modulo by zero
# ZeroDivisionError: integer division or modulo by zero
# ZeroDivisionError: integer division or modulo by zero
#---> 17 for s in samples: print s.fib
#
#AttributeError: 'Sample' object has no attribute 'fib'

- 更新 -

看来,关于futures库,python 3的行为与python 2不同。

futures_exceptions.py

from concurrent.futures import ThreadPoolExecutor, as_completed

def div_zero(x):
    return x / 0

with ThreadPoolExecutor(max_workers=4) as executor:
    futures = executor.map(div_zero, range(4))
    for future in as_completed(futures): print(future)

Python 2.7.6 输出:

Traceback (most recent call last):
  File "...futures_exceptions.py", line 12, in <module>
    for future in as_completed(futures):
  File "...python2.7/site-packages/concurrent/futures/_base.py", line 198, in as_completed
    with _AcquireFutures(fs):
  File "...python2.7/site-packages/concurrent/futures/_base.py", line 147, in __init__
    self.futures = sorted(futures, key=id)
  File "...python2.7/site-packages/concurrent/futures/_base.py", line 549, in map
    yield future.result()
  File "...python2.7/site-packages/concurrent/futures/_base.py", line 397, in result
    return self.__get_result()
  File "...python2.7/site-packages/concurrent/futures/_base.py", line 356, in __get_result
    raise self._exception
ZeroDivisionError: integer division or modulo by zero

Python 3.3.2 输出:

Traceback (most recent call last):
  File "...futures_exceptions.py", line 11, in <module>
    for future in as_completed(futures):
  File "...python3.3/concurrent/futures/_base.py", line 193, in as_completed
    with _AcquireFutures(fs):
  File "...python3.3/concurrent/futures/_base.py", line 142, in __init__
    self.futures = sorted(futures, key=id)
  File "...python3.3/concurrent/futures/_base.py", line 546, in result_iterator
    yield future.result()
  File "...python3.3/concurrent/futures/_base.py", line 392, in result
    return self.__get_result()
  File "...python3.3/concurrent/futures/_base.py", line 351, in __get_result
    raise self._exception
  File "...python3.3/concurrent/futures/thread.py", line 54, in run
    result = self.fn(*self.args, **self.kwargs)
  File "...futures_exceptions.py", line 7, in div_zero
    return x / 0
ZeroDivisionError: division by zero

3 个答案:

答案 0 :(得分:3)

我个人使用Futures,因为界面非常简单。对于回溯问题,我找到了一种解决方法来保护它。看看我对这个问题的回答:

Getting original line number for exception in concurrent.futures

答案 1 :(得分:2)

如果您想获取有关线程中未处理异常的信息并使用 ThreadPoolExecutor,您可以这样做:

anova_test

答案 2 :(得分:0)

简单的解决方案:使用最适合您的替代方案,并在您的员工中实施自己的try-except阻止。如果必须,请在根电话周围进行。

我不会说这些库处理异常&#34;错误&#34;。它们具有默认行为,无论多么原始。如果默认不适合你,你应该自己处理。

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