Question

我在这个问题上看到这个SO post无济于事。

我正在尝试解压缩来自网址的.gz文件。

url_file_handle=StringIO( gz_data )
gzip_file_handle=gzip.open(url_file_handle,"r")
decompressed_data = gzip_file_handle.read()
gzip_file_handle.close()

...但我得 TypeError：强制转换为Unicode：需要字符串或缓冲区，找到cStringIO.StringI

发生了什么事？

Traceback (most recent call last):  
  File "/opt/google/google_appengine-1.2.5/google/appengine/tools/dev_appserver.py", line 2974, in _HandleRequest
    base_env_dict=env_dict)
  File "/opt/google/google_appengine-1.2.5/google/appengine/tools/dev_appserver.py", line 411, in Dispatch
    base_env_dict=base_env_dict)
  File "/opt/google/google_appengine-1.2.5/google/appengine/tools/dev_appserver.py", line 2243, in Dispatch
    self._module_dict)
  File "/opt/google/google_appengine-1.2.5/google/appengine/tools/dev_appserver.py", line 2161, in ExecuteCGI
    reset_modules = exec_script(handler_path, cgi_path, hook)
  File "/opt/google/google_appengine-1.2.5/google/appengine/tools/dev_appserver.py", line 2057, in ExecuteOrImportScript
    exec module_code in script_module.__dict__
  File "/home/jldupont/workspace/jldupont/trunk/site/app/server/tasks/debian/repo_fetcher.py", line 36, in <module>
    main()
  File "/home/jldupont/workspace/jldupont/trunk/site/app/server/tasks/debian/repo_fetcher.py", line 30, in main
    gziph=gzip.open(fh,'r')
  File "/usr/lib/python2.5/gzip.py", line 49, in open
    return GzipFile(filename, mode, compresslevel)
  File "/usr/lib/python2.5/gzip.py", line 95, in __init__
    fileobj = self.myfileobj = __builtin__.open(filename, mode or 'rb')
TypeError: coercing to Unicode: need string or buffer, cStringIO.StringI found

Answer 1

如果您的数据已经在字符串中，请尝试zlib，声称完全兼容gzip：

import zlib
decompressed_data = zlib.decompress(gz_data, 16+zlib.MAX_WBITS)

了解详情：http://docs.python.org/library/zlib.html

Answer 2

gzip.open是打开文件的简写，你想要的是gzip.GzipFile，你可以传递一个文件块

open(filename, mode='rb', compresslevel=9)
    #Shorthand for GzipFile(filename, mode, compresslevel).

VS

class GzipFile
   __init__(self, filename=None, mode=None, compresslevel=9, fileobj=None)
   #    At least one of fileobj and filename must be given a non-trivial value.

所以这应该对你有用

gzip_file_handle = gzip.GzipFile(fileobj=url_file_handle)

Answer 3

如果您不想将晦涩的论据传递给gzip.GzipFile，请考虑使用zlib.decompress。

当您处理可能是gzip压缩或未压缩的urllib2.urlopen响应时：

import gzip
from StringIO import StringIO

# response = urllib2.urlopen(...

content_raw = response.read()
if 'gzip' in response.info().getheader('Content-Encoding'):
    content = gzip.GzipFile(fileobj=StringIO(content_raw)).read()

当您处理可以存储gzip压缩或未压缩数据的文件时：

import gzip

# some_file = open(...

try:
    content = gzip.GzipFile(fileobj=some_file).read()
except IOError:
    some_file.seek(0)
    content = some_file.read()

以上示例在Python 2.7中

Answer 4

您可以使用内置于gzip的Python库（适用于Python 3.2+）中的gzip.decompress。

有关如何解压缩字节的示例：

import gzip
gzip.decompress(gzip_data)

文档

https://docs.python.org/3.5/library/gzip.html#gzip.decompress

Python gzip：有没有办法从字符串解压缩？

4 个答案: