Question

好吧，我不知道如何使用指定的字符生成包含所有可能值的字符串。好的，我不知道如何解释它，所以这是一个例子：

chars：a, b, c

代：

abc
aab
abb
acc
baa
bbb
bbc
bac
cab
ccc
aaa
cbb
caa
ccb
cca
bab
bcb

我尝试过使用字符列表，然后迭代此列表中的每个字符，然后再次迭代列表中的每个字符，但是......让我们说它不起作用。

Answer 1

我自己在this question上的答案的副本：

这适用于a,b,c或任何其他连续字符序列：

import java.util.Arrays;
import java.util.Iterator;

public class BruteForceIterator implements Iterator<String> {

    private char min, max;

    private char[] current;

    private char[] last;

    private int reachedLast = 0;

    public BruteForceIterator(char min, char max, int length) {
        this.min = min;
        this.max = max;
        current = new char[length];
        Arrays.fill(current, min);
        last = new char[length];
        Arrays.fill(last, max);
    }

    @Override
    public boolean hasNext() {
        return reachedLast < 2;
    }

    @Override
    public String next() {
        String str = new String(current);
        for(int i = current.length - 1; i >= 0; i--) {
            char next = following(current[i]);
            current[i] = next;
            if (next != min) {
                break;
            }
        }
        if (Arrays.equals(current, last) || reachedLast > 0) {
            reachedLast++;
        }
        return str;
    }

    private char following(char in) {
        if (in < max) {
            return (char) (in + 1);
        } else {
            return min;
        }
    }

    @Override
    public void remove() {
        throw new UnsupportedOperationException("No with me, sir!");
    }

    public static void main(String[] args) {
        BruteForceIterator bit = new BruteForceIterator('a', 'c', 3);
        while (bit.hasNext()) {
            System.out.println(bit.next());
        }
    }
}

Answer 2

我很快就在下面编写了这段代码。您可能需要对其进行编辑以使其工作或适应您的需求我只想与您分享我的代码的想法。但是我会推荐jlordo的答案，因为它效率更高。

Array String[] = new Array[]{"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"}
ArrayList<String> numbersrandom;
for(int a = 0; i <= 26; i++){
for(int b = 0; i <= 26; i++){
for(int c = 0; i <= 26; i++){
numbersrandom.add(String[a]+String[b]+String[c]);
}
}
}

使用此代码后，您可以使用随机生成器和for循环随机混合这些代码。祝你好运！

生成具有指定字符的随机字符串？

2 个答案: