我必须比较XML中的两个文件，其中我需要显示“文件之间无法匹配的模式的内容，无论是节点名称还是节点值的差异。”
到目前为止我写的代码是
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.XPath;
namespace ConsoleApplication1
{
public class Program
{
public Program()
{
XmlDocument _mxml1 = new XmlDocument();
_mxml1.Load(@"C:\Users\Rahul\Documents\xml work\abcd.xml");
XmlDocument _mxml2 = new XmlDocument();
_mxml2.Load(@"C:\Users\Rahul\Documents\xml work\efg.xml");
XmlElement _melement1 = _mxml1.DocumentElement;
XmlElement _melement2 = _mxml2.DocumentElement;
XPathNavigator nav1 = _mxml1.CreateNavigator();
XPathNavigator nav2 = _mxml2.CreateNavigator();
if (_melement1.HasChildNodes && _melement2.HasChildNodes && _melement1.ChildNodes.Count == _melement2.ChildNodes.Count)
{
XmlNodeList _node1 = _melement1.ChildNodes;
XmlNodeList _node2 = _melement2.ChildNodes;
foreach (XmlNode _n1 in _node1)
{
foreach (XmlNode _n2 in _node2)
{
int count = _n1.ChildNodes.Count;
int count2 = _n2.ChildNodes.Count;
if (_n1.Name.ToString() == _n2.Name.ToString())
{
int res = _n1.OuterXml.CompareTo(_n2.OuterXml);
if (res == 1)
{
Console.WriteLine("All the child names match for the case ");
}
if (_n1.InnerText.ToString() != _n2.InnerText.ToString())
{
Console.WriteLine("Values of some child doesnot match");
// here we need to traverse through child nodes of both xmls to find out the change in file..
}
if (_n1.InnerXml.ToString() == _n2.InnerXml.ToString())
{
Console.WriteLine("Records match completly");
}
}
else
{
Console.WriteLine("XML_1 " + " " + "" + "XML_2 \n" + _n1.Name + " " + _n2.Name);
}
}
}
}
}
static void Main(string[] args)
{
Program obj = new Program();
}
}
}
现在问题是如果节点的值有差异怎么能找到两个文件中不同的字符串部分......