Postgresql:选择distinct - 列的组合

时间:2013-03-20 18:50:52

标签: postgresql select distinct-values

我在PostgreSQL中有这个查询:

select p1.id, p2.id, p1.title, p2.title 
from publication "p1", publication "p2"
where p1.title = p2.title and p1.id <> p2.id

问题是它返回的数据超出了我的需要:

id    id   title          title  
3456  5678 Ulysses        Ulysses  
5678  3456 Ulysses        Ulysses  
234,  345  Das Kapital    Das Kapital  
345   234  Das Kapital    Das Kapital 

我只需要第1行和第3行,或第2行和第4行。

3 个答案:

答案 0 :(得分:3)

select p1.id, p2.id
 , p1.title, p2.title
from publication p1
    , publication p2
where p1.title = p2.title
  and p1.id < p2.id -- tie breaker
  ;

或者使用更加简洁的JOIN语法:

SELECT p1.id, p2.id
 , p1.title, p2.title
FROM publication p1
JOIN publication p2 ON p1.title = p2.title
                   AND p1.id < p2.id -- tie breaker
  ;

答案 1 :(得分:0)

我有一个简单的想法来实现你的场景。

select p1.id, p2.id, p1.title, p2.title , sum(p1.id + p2.id) as temp
from publication "p1", publication "p2" group by temp

答案 2 :(得分:0)

select DISTINCT p1.id, p2.id, p1.title, p2.title 
from publication "p1", publication "p2"
where p1.title = p2.title
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