Question

我有以下字典，它是从XML Parser中提取的。使用github库从以下链接解析XML文件。

 Quiz = { 
questions = (
    {
    "@id" = 1;
    answer = D;
    A = "Under the rock";
    B = "Trees";
    C = "Mountain";
    D = Water;
    question = "Where does the fish live?";
    },
    {
    "@id" = 2;
    answer = D;
    A = "Four";
    B = "Two";
    C = "Six";
    D = Three;
    question = "How many legs for a rabbit?";
    },......
    };

我正在尝试检索关键问题，答案，选项1-4的对象。但有些我怎么也不能传递价值。

for (NSString * key in xmlDictionary) {
        NSDictionary * subDict = [xmlDictionary objectForKey:@"questions"];
        NSLog(@"Correct Answers \n\n%@", [subDict objectForKey:@"answer"]);
        // all your other code here.
    }

不认为任何价值正在回归。实际上我在xml中有10个元素，在解析过程中它显示我有10个计数。但是，当我尝试计算xmlDictionary并返回1.不确定这里出了什么问题？

另外，我将如何提取所有值取决于@id？

困惑!!!

更新：我在XML文件中将...标签更改为...

NSDictionary *currentObject;
    if (rowIndex < countXML)
    {
        currentObject=[muteArr objectAtIndex:rowIndex];
    }
    else
    {
        [self performSegueWithIdentifier:@"simple" sender:self];
    }

    NSString *questionLbl = [currentObject objectForKey:@"question"];
    NSString *op1Lbl = [currentObject objectForKey:@"A"];
    NSString *op2Lbl = [currentObject objectForKey:@"B"];
    NSString *op3Lbl = [currentObject objectForKey:@"C"];
    NSString *op4Lbl = [currentObject objectForKey:@"D"];
    NSString *answer = [currentObject objectForKey:@"answer"];
    NSString *questNoLbl = [currentObject objectForKey:@"@ID"];

questionID.text = [@"Question # " stringByAppendingString:questNoLbl];
    question.text = questionLbl;

    [answer1 setTitle:op1Lbl forState:UIControlStateNormal];
    [answer2 setTitle:op2Lbl forState:UIControlStateNormal];
    [answer3 setTitle:op3Lbl forState:UIControlStateNormal];
    [answer4 setTitle:op4Lbl forState:UIControlStateNormal];

现在我有了这个代码，可以检索每个问题并在QuizViewController中显示它。当用户按下按钮时，它应该查看新的控制器并显示答案是否正确，并在单击ResultViewController中的“继续”按钮后返回到QuizViewController。现在我有了所有这些设置。

现在想在ResultViewController中显示答案是否正确。

Answer 1

使用此行

NSDictionary * subDict = [xmlDictionary objectForKey:@"questions"];

你得到了相同的字典，你已经有了。

试试这个：

for (NSString * key in xmlDictionary) {
    NSDictionary * subDict = [xmlDictionary objectForKey:key];
    NSLog(@"Correct Answers \n\n%@", [subDict objectForKey:@"answer"]);
    // all your other code here.
}

使用您编辑的XML结构，您应该这样做：

NSDictionary * rootDict = [xmlDictionary objectForKey:@"questions"];
for (NSString * key in rootDict) {
        NSDictionary * subDict = [rootDict objectForKey:key];
        NSLog(@"Correct Answers \n\n%@", [subDict objectForKey:@"answer"]);
        // all your other code here.
    }

检索NSDictionary对象

1 个答案: