这是我的代码,但这适用于单个文件解决方案。
我可以共享多个文件吗?像上面的单个文件一样上传?
Button btn = (Button)findViewById(R.id.hello);
btn.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
Intent intent = new Intent(Intent.ACTION_SEND);
String path = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS) + "/pic.png";
File file = new File(path);
MimeTypeMap type = MimeTypeMap.getSingleton();
intent.setType(type.getMimeTypeFromExtension(MimeTypeMap.getFileExtensionFromUrl(path)));
intent.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(file));
intent.putExtra(Intent.EXTRA_TEXT, "1111");
startActivity(intent);
}
});
答案 0 :(得分:79)
是的,但您需要使用Intent.ACTION_SEND_MULTIPLE
代替Intent.ACTION_SEND
。
Intent intent = new Intent();
intent.setAction(Intent.ACTION_SEND_MULTIPLE);
intent.putExtra(Intent.EXTRA_SUBJECT, "Here are some files.");
intent.setType("image/jpeg"); /* This example is sharing jpeg images. */
ArrayList<Uri> files = new ArrayList<Uri>();
for(String path : filesToSend /* List of the files you want to send */) {
File file = new File(path);
Uri uri = Uri.fromFile(file);
files.add(uri);
}
intent.putParcelableArrayListExtra(Intent.EXTRA_STREAM, files);
startActivity(intent);
这肯定可以简化,但我留下了一些线,这样你就可以分解所需的每一步。
UPDATE :从API 24开始,共享文件URI将导致FileUriExposedException。要解决此问题,您可以将compileSdkVersion切换为23或更低,也可以使用content URIs with a FileProvider。
更新(更新):Google recently announced需要新的应用和应用更新才能定位其中一个最新版本的Android,以便发布到Play商店。也就是说,如果您计划将应用程序发布到商店,则定位API 23或更低版本不再是有效选项。你必须去FileProvider路线。
答案 1 :(得分:5)
以下是MCeley解决方案即兴创作的改进版本。这可以用于发送异构文件列表(如图像,文档和视频),例如同时上传下载的文档,图像。
public static void shareMultiple(List<File> files, Context context){
ArrayList<Uri> uris = new ArrayList<>();
for(File file: files){
uris.add(Uri.fromFile(file));
}
final Intent intent = new Intent(Intent.ACTION_SEND_MULTIPLE);
intent.setType("*/*");
intent.putParcelableArrayListExtra(Intent.EXTRA_STREAM, uris);
context.startActivity(Intent.createChooser(intent, context.getString(R.string.ids_msg_share)));
}
答案 2 :(得分:1)
/*
manifest file outside the applicationTag write these permissions
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
<uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" /> */
File pictures = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_PICTURES);
//Get a top-level public external storage directory for placing files of a particular type.
// This is where the user will typically place and manage their own files,
// so you should be careful about what you put here to ensure you don't
// erase their files or get in the way of their own organization...
// pulled from Standard directory in which to place pictures that are available to the user to the File object
String[] listOfPictures = pictures.list();
//Returns an array of strings with the file names in the directory represented by this file. The result is null if this file is not a directory.
Uri uri=null;
ArrayList<Uri> arrayList = new ArrayList<>();
if (listOfPictures!=null) {
for (String name : listOfPictures) {
uri = Uri.parse("file://" + pictures.toString() + "/" + name );
arrayList.add(uri);
}
Intent intent = new Intent();
intent.setAction(Intent.ACTION_SEND_MULTIPLE);
intent.putExtra(Intent.EXTRA_STREAM, arrayList);
//A content: URI holding a stream of data associated with the Intent, used with ACTION_SEND to supply the data being sent.
intent.setType("image/*"); //any kind of images can support.
chooser = Intent.createChooser(intent, "Send Multiple Images");//choosers title
startActivity(chooser);
}
答案 3 :(得分:0)
如果要在运行KitKat及更高版本的设备上与其他应用程序共享文件,则需要提供Uri权限。
这是我处理KitKat前后多个文件共享的方式:
//All my paths will temporarily be retrieve into this ArrayList
ArrayList<PathModel> pathList;
//All Uri's are stored in this ArrayList
ArrayList<Uri> uriArrayList = null;
//This is important since we are sending multiple files
Intent sharingIntent = new Intent(Intent.ACTION_SEND_MULTIPLE);
//Used temporarily to get Uri references
Uri shareFileUri;
if (android.os.Build.VERSION.SDK_INT < Build.VERSION_CODES.KITKAT) {
//My paths are store in SQLite, I retrieve them first
SQLiteHelper helper = new SQLiteHelper(this);
//Temporarily store file paths
pathList = helper.getAllAttachments(viewholderID);
helper.close();
//Create new instance of the ArrayList where the Uri will be stored
uriArrayList = new ArrayList<>();
//Get all paths from my PathModel ArrayList
for (PathModel data : pathList) {
//Create a new file for each path
File mFile = new File(data.getPath());
//No need to add Uri permissions for pre-KitKat
shareFileUri = Uri.fromFile(mFile);
//Add Uri's to the Array that holds the Uri's
uriArrayList.add(shareFileUri);
}
} else {
//My paths are store in SQLite, I retrieve them first
SQLiteHelper helper = new SQLiteHelper(this);
//Temporarily store file paths
pathList = helper.getAllAttachments(viewholderID);
helper.close();
//Create new instance of the ArrayList where the Uri will be stored
uriArrayList = new ArrayList<>();
//Get all paths from my PathModer ArrayList
for (PathModel data : pathList) {
//Create a new file for each path
File mFile = new File(data.getPath());
//Now we need to grant Uri permissions (kitKat>)
shareFileUri = FileProvider.getUriForFile(getApplication(), getApplication().getPackageName() + ".provider", mFile);
//Add Uri's to the Array that holds the Uri's
uriArrayList.add(shareFileUri);
}
//Grant read Uri permissions to the intent
sharingIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
}
//I know the files that will be sent will one of the following
sharingIntent.setType("application/pdf/*|image|video/*");
//pass the Array that holds the paths to the files
sharingIntent.putParcelableArrayListExtra(Intent.EXTRA_STREAM, uriArrayList);
//Start intent by creating a chooser
startActivity(Intent.createChooser(sharingIntent, "Share using"));
在我的情况下,路径存储在SQLite
中,但是路径可以来自任何地方。