Question

我有一个字符串说：

<encoded:2,Message request>

现在我想从上面的行中提取2和Message request。

private final String pString = "<encoded:[0-9]+,.*>";
    private final Pattern pattern = Pattern.compile(pString);

    private void parseAndDisplay(String line) {

        Matcher matcher = pattern.matcher(line);
        if (matcher.matches()) {
            while(matcher.find()) {
                String s = matcher.group();
                System.out.println("=====>"+s);

            }
        }
    }

这不会检索它。有什么问题

Answer 1

您必须在正则表达式中定义组：

"<encoded:([0-9]+),(.*?)>"

或

"<encoded:(\\d+),([^>]*)"

Answer 2

试

    String s = "<encoded:2,Message request>";
    String s1 = s.replaceAll("<encoded:(\\d+?),.*", "$1");
    String s2 = s.replaceAll("<encoded:\\d+?,(.*)>", "$1");

Answer 3

尝试

"<encoded:([0-9]+),([^>]*)"

另外，正如其他评论中所建议的那样，请使用group(1)和group(2)

Answer 4

试试这个：

         Matcher matcher = Pattern.compile("<encoded:(\\d+)\\,([\\w\\s]+)",Pattern.CASE_INSENSITIVE).matcher("<encoded:2,Message request>");

    while (matcher.find()) {
        System.out.println(matcher.group(1));
        System.out.println(matcher.group(2));
    }

从字符串中提取子字符串 - 正则表达式

4 个答案: