Question

我正在开发一个Android应用程序，我需要发送单个消息一次接收多个模拟器。但问题只有一个模拟器正在接收消息。这是我的代码。

公共类SMS扩展活动 {

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) 
{
    super.onCreate(savedInstanceState);

    setContentView(R.layout.main);

    btnSendSMS = (Button) findViewById(R.id.btn_SendSms);

    txtPhoneNo = (EditText) findViewById(R.id.edittext_PhoneNumber);

    txtMessage = (EditText) findViewById(R.id.edittext_MessageBody);

    btnSendSMS.setOnClickListener(new View.OnClickListener() 

    {
        public void onClick(View v) 

        {                
            String message = txtMessage.getText().toString();

            String phoneNo = txtPhoneNo.getText().toString();

            StringTokenizer st=new StringTokenizer(phoneNo,",");

            while (st.hasMoreElements())

            {
                String tempMobileNumber = (String)st.nextElement();

                if(tempMobileNumber.length()>0 && message.trim().length()>0)

                {
                    sendSMS(tempMobileNumber, message);
                }

                else 

                {
                    Toast.makeText(getBaseContext(), 

                            "Please enter both phone number and message.", 

                            Toast.LENGTH_SHORT).show();
                }
            }

        }
    });  

}


private void sendSMS(String phoneNumber, String message)

{
    String SENT = "SMS_SENT";

    String DELIVERED = "SMS_DELIVERED";

    PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(SENT), 0);

    PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0, new Intent(DELIVERED), 0);

  //---when the SMS has been sent---
    registerReceiver(new BroadcastReceiver()

    {
        @Override
        public void onReceive(Context arg0, Intent arg1) 

        {
            switch (getResultCode())


            {

                case Activity.RESULT_OK:


                    Toast.makeText(getBaseContext(), "SMS sent", 

                            Toast.LENGTH_SHORT).show();
                    break;

                case SmsManager.RESULT_ERROR_GENERIC_FAILURE:


                    Toast.makeText(getBaseContext(), "Generic failure",

                            Toast.LENGTH_SHORT).show();

                    break;

                case SmsManager.RESULT_ERROR_NO_SERVICE:

                    Toast.makeText(getBaseContext(), "No service", 

                            Toast.LENGTH_SHORT).show();
                    break;

                case SmsManager.RESULT_ERROR_NULL_PDU:

                    Toast.makeText(getBaseContext(), "Null PDU", 

                            Toast.LENGTH_SHORT).show();
                    break;

                case SmsManager.RESULT_ERROR_RADIO_OFF:

                    Toast.makeText(getBaseContext(), "Radio off", 

                            Toast.LENGTH_SHORT).show();
                    break;
            }
        }
    } , new IntentFilter(SENT));



    SmsManager sms = SmsManager.getDefault();

    sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI);       
}

}

Answer 1

要将SMS消息发送到在同一台计算机上运行的另一个仿真器实例，请启动SMS应用程序。指定目标仿真器实例的控制台端口号（例如：5555）和SMS地址。

请注意，此答案基于：Linuxtopia指南。

Answer 2

您可以创建模拟器ID或数字的数组，然后将 sendTextMessage 放入执行循环的数组中。或者您可以拥有允许用户将电话号码或模拟器号码插入列表和上述相同程序的UI！请注意 sendTextMessage 的第一个参数是“电话号码”，您要向其发送短信只需将其作为循环迭代替换为您的要求

在多个模拟器上发送短信

2 个答案: