Question

我在android资产中放了一个zip文件。如何在android内部存储中提取文件？我知道如何获取文件，但我不知道如何提取它。这是我的代码..

Util zip ;

zip = new Util();

zip.copyFileFromAsset(this, "myfile.zip", getExternalStorage()+ "/android/data/edu.binus.profile/");

感谢您的帮助：D

Answer 1

这段代码可以帮助你....只需将zipfile位置和你想要提取文件的位置传递给这个类，同时制作一个对象...并调用解压缩方法...

    public class Decompress { 
  private String zip; 
  private String loc; 

  public Decompress(String zipFile, String location) { 
    zip = zipFile; 
    loc = location; 

    dirChecker(""); 
  } 

  public void unzip() { 
    try  { 
      FileInputStream fin = new FileInputStream(zip); 
      ZipInputStream zin = new ZipInputStream(fin); 
      ZipEntry ze = null; 
      while ((ze = zin.getNextEntry()) != null) { 
        Log.v("Decompress", "Unzipping " + ze.getName()); 

        if(ze.isDirectory()) { 
          dirChecker(ze.getName()); 
        } else { 
          FileOutputStream fout = new FileOutputStream(loc + ze.getName()); 
          for (int c = zin.read(); c != -1; c = zin.read()) { 
            fout.write(c); 
          } 

          zin.closeEntry(); 
          fout.close(); 
        } 

      } 
      zin.close(); 
    } catch(Exception e) { 
      Log.e("Decompress", "unzip", e); 
    } 

  } 

  private void dirChecker(String dir) { 
    File f = new File(_location + dir); 

    if(!f.isDirectory()) { 
      f.mkdirs(); 
    } 
  } 
}

Answer 2

基于Sreedev R解决方案，我添加了从资源中读取文件的选项并使用缓冲区：

package com.pixoneye.api.utils;

import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;

import android.content.Context;
import android.util.Log;

public class Decompress {
    private static final int BUFFER_SIZE = 1024 * 10;
    private static final String TAG = "Decompress";

    public static void unzipFromAssets(Context context, String zipFile, String destination) {
        try {
            if (destination == null || destination.length() == 0)
                destination = context.getFilesDir().getAbsolutePath();
            InputStream stream = context.getAssets().open(zipFile);
            unzip(stream, destination);
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    public static void unzip(String zipFile, String location) {
        try {
            FileInputStream fin = new FileInputStream(zipFile);
            unzip(fin, location);
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        }

    }

    public static void unzip(InputStream stream, String destination) {
        dirChecker(destination, "");
        byte[] buffer = new byte[BUFFER_SIZE];
        try {
            ZipInputStream zin = new ZipInputStream(stream);
            ZipEntry ze = null;

            while ((ze = zin.getNextEntry()) != null) {
                Log.v(TAG, "Unzipping " + ze.getName());

                if (ze.isDirectory()) {
                    dirChecker(destination, ze.getName());
                } else {
                    File f = new File(destination, ze.getName());
                    if (!f.exists()) {
                        boolean success = f.createNewFile();
                        if (!success) {
                            Log.w(TAG, "Failed to create file " + f.getName());
                            continue;
                        }
                        FileOutputStream fout = new FileOutputStream(f);
                        int count;
                        while ((count = zin.read(buffer)) != -1) {
                            fout.write(buffer, 0, count);
                        }
                        zin.closeEntry();
                        fout.close();
                    }
                }

            }
            zin.close();
        } catch (Exception e) {
            Log.e(TAG, "unzip", e);
        }

    }

    private static void dirChecker(String destination, String dir) {
        File f = new File(destination, dir);

        if (!f.isDirectory()) {
            boolean success = f.mkdirs();
            if (!success) {
                Log.w(TAG, "Failed to create folder " + f.getName());
            }
        }
    }
}

Answer 3

也许您应该尝试将FileOutputStream与zip文件中的输入流结合使用。使用包文件，这应该可以。

从this question引用@wordy：

PackageManager pm = context.getPackageManager();
String apkFile = pm.getApplicationInfo(context.getPackageName(), 0).sourceDir;
ZipFile zipFile = new ZipFile(apkFile); 
ZipEntry entry = zipFile.getEntry("assets/FILENAME");
myInput = zipFile.getInputStream(entry);
myOutput = new FileOutputStream(file);
    byte[] buffer = new byte[1024*4];
int length;
int total = 0;
int counter = 1;
while ((length = myInput.read(buffer)) > 0) {
    total += length;
    counter++;
    if (counter % 32 == 0) {
        publishProgress(total);
    }
        myOutput.write(buffer, 0, length);
}

看起来ProGuard可能存在问题，但希望代码示例适合您。

Answer 4

我还没有测试过，但在OCR上做项目时，我遇到了这个library，其中有从网络中解压缩下载文件的方法。解压缩文件的确切方法是在class下找到的installZipFromAssets(String sourceFilename,File destinationDir,File destinationFile)。希望这就是您要找的内容

Answer 5

您还可以使用zip4j外部库，它提供加密等附加功能。此外，它还具有将文件提取到路径的特定位置的功能。

在Android资源中解压缩文件

5 个答案: