Question

我已经问过（并解决了）一些接近的事情 here 但现在更复杂了。我有相同的BID表：

Id_auction        bidder_1      winner_1    bidder_2    winner_2    item
  1                Alice           1          Ben         1          cup
  2               Charles          0          Alice       1          mug
  3                 Ben            1          Charles     1          pen

但现在我想加入另一张表USD

的信息

Id_auction         USD
1                  100
2                  150
3                   50

如果竞标者是胜利者，如果不是赢家，则价值为1.值为0.因此，在第一次拍卖中，Alice和Ben是赢家，在第二次只有Alice获胜。我需要一个MySQL查询，所以结果将是这样的：

  Id_auction       bidder        item      bidder_number   USD
  1                Alice         cup            1          100
  1                Ben           cup            2          100
  2                Alice         mug            2          150
  3                Ben           pen            1           50
  3                Charles       pen            2           50

谢谢！

Answer 1

只需JOIN使用此表格USD：

SELECT sub.*, USD.USD
FROM
(
  SELECT 
    t1.id_auction,
    t2.bidder_1 AS bidder,
    t2.item,
    1 AS bidder_number    
  FROM table1 t1
  INNER JOIN table1 t2  ON t1.id_auction = t2.id_auction
                       AND t2.winner_1 = 1
  UNION ALL
  SELECT 
    t1.id_auction,
    t2.bidder_2 AS bidder,
    t2.item,
    2                    
  FROM table1 t1
  INNER JOIN table1 t2  ON t1.id_auction = t2.id_auction
                       AND t2.winner_2 = 1
) AS sub
INNER JOIN USD ON sub.id_auction = USD.id_auction
ORDER BY id_auction, bidder;

Updated SQL Fiddle Demo

| ID_AUCTION |  BIDDER | ITEM | BIDDER_NUMBER | USD |
-----------------------------------------------------
|          1 |   Alice |  cup |             1 | 100 |
|          1 |     Ben |  cup |             2 | 100 |
|          2 |   Alice |  mug |             2 | 150 |
|          3 |     Ben |  pen |             1 |  50 |
|          3 | Charles |  pen |             2 |  50 |

Answer 2

SELECT
  BID.Id_auction AS Id_auction,
  BID.bidder_1 AS bidder,
  BID.item AS item,
  USD.USD AS USD,
  1 AS bidder_number
FROM BID
INNER JOIN USD ON BID.Id_auction=USD.Id_auction
WHERE BID.winner_1=1

UNION ALL

SELECT
  BID.Id_auction AS Id_auction,
  BID.bidder_2 AS bidder,
  BID.item AS item,
  USD.USD AS USD,
  2 AS bidder_number
FROM BID
INNER JOIN USD ON BID.Id_auction=USD.Id_auction
WHERE BID.winner_2=1

ORDER BY BID.Id_auction, budder_number

从不同列和两个表中选择数据

2 个答案: